Search results

  1. S

    Physical pendulum: frequency of rotated square

    I={(1/12)mL^2}+{m(L^2)/4}=(mL^2)/3 then you should multiply it by 4 so: I=(4/3)*(mL^2) this is for the center of mass of the square and for the support you should just add 4m{(L/2)sqrt(2)}^2
Top