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  1. I

    Solving csc x + 2 for 0

    Haha...thanks for the help. :cry:
  2. I

    Solving csc x + 2 for 0

    Oh jeez, I'm such an idiot. I hate making little mistakes like that. So the answer is B. then since 7\pi/6 is in Quadrant 3?
  3. I

    Solving csc x + 2 for 0

    Tangent is positive in Quadrant 3 (ASTC as I learned it), so wouldn't sine be negative there? I asked my dad about this too and he said that the answer is B. but I don't understand because 7\pi/6 is in the third quadrant and isn't that negative if it's sine?
  4. I

    Solving csc x + 2 for 0

    Ohhhh, ok. So \pi/6 is in Quadrant I so that's correct and then 5\pi/6 is in Quad. 2 so that's also correct but 7\pi/6 is in Quad. 3 which is negative. So the answer is A.?
  5. I

    Solving csc x + 2 for 0

    [SOLVED] Solving csc x + 2 for 0 Homework Statement "Solve csc x + 2 = 0 for 0 <= x < 2 \pi Choices are: A. \pi/6 and 5\pi/6 B. \pi/6 and 7\pi/6 C. 4\pi/3 and 5\pi/3 D. 7\pi/6 and 11\pi/6 Homework Equations csc x =2 sin x = 1/2 = 30 degrees = \pi/6 The Attempt at a...
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