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1. ### Centrifugal Force- Finding Speed of Satellite

Homework Statement In order for a satellite to move in a stable circular orbit of radius 6736 km at a constant speed, its centripetal acceleration must be inversely proportional to the square of the radius r of the orbit. What is the speed of the satellite? The universal gravitational constant...
2. ### Vectors. Calculating Weight (N) of Plane with force and angle of take off

Homework Statement On takeoff” refers to after the plane has left the ground. On takeoff, the combined action of the air around the engines and wings of an airplane exerts a(n) 8445 N force on the plane, directed upward at an angle of 50.2◦ above the hori- zontal. The plane rises with...
3. ### Stopping Distance with Vi and Coefficient of friction.

Yes this is correct. Thank you very much!
4. ### Stopping Distance with Vi and Coefficient of friction.

What is the formula for that. This is just a guess. T=A/Ff? So T=29900/1274? T=23.47s? And then i used the kinematics equation DeltaX= vf+vi/2 x t and got 350.88 m
5. ### Stopping Distance with Vi and Coefficient of friction.

No it doesnt i was wrong. F=mass x acceleration. Acceleration is 0 because it is a constant velocity. So wouldn't that mean that force=0 because 1000kg x 0= 0. So then wouldn't there only be force of friction?
6. ### Stopping Distance with Vi and Coefficient of friction.

Well i plugged in 1000kg for mass and got 9800N for normal force so Ff=1274N. Not i need to figure out what to do with Ff. If the mass is 1000kg then it is raveling with a force of 29900N (F=MV). So there is 29900N forcer going forward and a 1275.3N Force of friction. I do not know what i do...
7. ### Stopping Distance with Vi and Coefficient of friction.

Which formulas? The Ff=(FN)(mu) ?
8. ### Stopping Distance with Vi and Coefficient of friction.

Homework Statement A car is traveling at 66.9 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s2 . If the coefficient of friction between road and tires on a rainy day is 0.13, what is the minimum distance in which the car will stop? (1 mi = 1.609) Answer in units of m...