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  1. F

    Integral optimization

    Homework Statement A circular disk of radius r is used in an evaporator and is rotated in a vertical plane. If it is to be partially submerged in the liquids as to maximize the exposed wetted area of the disk, show that the center of the disk should be positioned at a height r/ \sqrt{1+\pi^2}...
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    What volume of this solution is required to make 1.25 L

    v1 = c2v2/c1 v1 = (1.25 L)(2.75 mol/L)/(15.8585 mol/L) = 0.217 L.
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    Neutralization reaction

    If you multiply the H3PO4 by 3, you would have a ratio of 1:1 with NaOH:H3PO4. So you could write c1v1=3c2v2?
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    Inverse trig functions

    ahhh so could I write sinA = \theta?
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    Inverse trig functions

    Homework Statement Determine sin(arctan(3)) The Attempt at a Solution I do not know how to start this. No special triangles : (.
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    Trig ratios

    sin(pi)= 0 cos (pi) = -1 tan (pi) =0. Is that all?
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    Trig ratios

    Homework Statement Find the trigonometric ratios sin\theta, cos\theta, tan\theta for the angle \theta = 14\pi. If a ratio does not exist or is undefined, write "DNE". The Attempt at a Solution I know that the other equivalent angle for 15pi is just pi. But I do not know how to write the...
  8. F

    What volume of this solution is required to make 1.25 L

    (0.85)(1.83 g/mL)(1000 mL/L)(1 mol/98.086 g) This gives you the concentration Then you can simply find the volume with c1v1=c2v2.
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    Neutralization reaction

    The H3PO4. This way you would have a 1:1 ration, correct?
  10. F

    Neutralization reaction

    Yes, I learnt the hard way. I wrote the balanced equation of H3PO4 + 3 NaOH -> 3 H2O + Na3PO4 3CnaohVnaoh = Ch3po4Vh3po4 Is this wrong?
  11. F

    What volume of this solution is required to make 1.25 L

    That's what's confusing me. If I do this, I get the wrong answer.
  12. F

    What volume of this solution is required to make 1.25 L

    Homework Statement An aqueous stock solution is 85.0% H2SO4 by mass and its density is 1.83 g/mL. What volume of this solution is required to make 1.25 L of 2.75 mol/L H2SO4(aq)? Give your answer in millilitres, accurate to three significant figures. Homework Equations c1v1=c2v2 The...
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    Neutralization reaction

    But I'm trying to find the volume of NaOH. There's 3:1 ratio.
  14. F

    Neutralization reaction

    so, 3c1v1 = c2v2 then v1 = c2v2/3c1 ? This would give me 6.80x10^-2 L.
  15. F

    Neutralization reaction

    The equation is wrong?
  16. F

    Neutralization reaction

    Homework Statement what volume of 0.350 mol/L NaOH(aq) is required to completely neutralize 54.5 mL of 1.31 mol/L H3PO4(aq)? Homework Equations c1v1 = c2v2 The Attempt at a Solution You would just solve for v2 but I am not getting the right answer for some reason.
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    Inverse ln function

    Can someone explain this?
  18. F

    Inverse ln function

    So my domain for the original function is wrong too? How? It cannot go past e^2 or otherwise you'd have a negative square root.
  19. F

    Inverse ln function

    I'm going to presume and say I am wrong. Now, I am more confused!
  20. F

    Inverse ln function

    Explain. when x = 8, it doesn't exist.
  21. F

    Inverse ln function

    I have another question of inverse ln. Let's say you have -(ln (x)+2)^{1/2} The domain would just be 0 < x </= e^2 The inverse of it would be x = e^{(-y^2 + 2)} Would the domain of the inverse function just be x < 0? which is the range of the original function.
  22. F

    Inverse ln function

    Is the answer -1.414?
  23. F

    Inverse ln function

    ugh this is so confusing :/
  24. F

    Inverse ln function

    What the? I never even knew that's possible. I just sub that into the quadratic formula with c = (e^{y}+28)
  25. F

    Inverse ln function

    But it's not equal to zero :/. I would just get -1.4 and 4/7.
  26. F

    Inverse ln function

    Yeah, the second part is undefined as you cannot take the ln of a negative number. So should I discard that root and write y = ln (4-7x) and solve for x out of here?
  27. F

    Inverse ln function

    Yeah. But I don't think it would work here. Would it?
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