Ah I see, but where would I go from there? I feel like I'm still missing something since when using a similar form to the integral I have set up above. I still get answers that are to the 11th power of 10 versus where they should be around the 5th power of 10.
I'll try as best as I can using a computer.
(A) q(t) = int(3 dt) from 0 - 14400 s.
q(t) = 3t| from 0 - 14400 s
q(t) = 43.2 kC
(B) V = (10 + 1/2t) x (60 min/hr) x (60 sec/min) = 36000 + 1800t
P = IV = 3(36000 + 1800t) = 5400t + 108000
W = int(5400t + 108000 dt) from 0 -...
Homework Statement
A constant current of 3A for 4 hours is required to charge an automotive battery. If the terminal voltage is 10 + 1/2 t V, where t is in hours,
(a) how much charge is transported as a result of the charging?
(b) how much energy is expended?
(c) how much does the charging...