Alright so if I lable the force between 4kN and 10kN F1 and from 10kN to 8kN F2 and place an pivot at the left hand side of the bridge would this be correct and what would the equation be for the clockwise rotation= counter clockwise rotation ?
As seen below...
So if I replace L with 2 I get T=600/sin50 meaning T=783.
Now im stuck with the following question http://img63.imageshack.us/img63/5889/klrk3.th.jpg [Broken].
I cant seem to understand how to work the answer out.
Ah yes I see if we replace L with 1 we get 1.5=1.5 meaning the formula becomes 300*L=L*T*Sin30 meaning T=600N.
The next question im stuck on is http://img63.imageshack.us/img63/4524/yhse1.th.jpg [Broken]
I would think the answer is 300*L=L*T*Sin50 .
Right to in problem 1 we basically made it perpendicular correct ? So for now lets call the lenght L meaning that 200*L=200*T*sin30, sin30 because that will give use the hypotenues which is T but the problem with the formula is that it gives the same answer as we got in question 1 meaning we...
Alright so the perpendicular distance is changing its now at the mid point the half of 0.5 is 0.25 and due to the fact that the force has moved half way I assume the distance is now half as well thus making it 0.25.