Hi, rock.freak667, isn't your answer the amount of the original remaining (not lost)? I'm not sure, I'll check my work again. Man's kinetic energy isn't effected much but spitball's is - I think that's what makes me uncomfortable about these problem w/o numbers - harder to get an intuitive...
A particle of mass m1 and velocity u1 collides with a particle of mass m2 at rest. The two particles stick together. What fraction of the original kinetic energy is lost in the collision?
Conservation of momentum law
The Attempt at a Solution...
A cannon in a fort overlooking the ocean fires a shell of mass M at an elevation angle, theta and muzzle velocity, v0. At the highest point, the shell explodes into two fragments (masses m1 + m2 = M), with an additional energy E, traveling in the original horizontal...
I'm from the US, so I'm not too familiar with Canada's secondary school system. You guys probably have tougher schools than us, so the following may not apply. That said, with your scores, engineering or physics may not be the best choice (unless, of course, you really weren't applying...
As a person with an undergrad degree in math who is now studying physics, here's my take:
The math required in physics is different than the math required for math's sake (I'm not too far along in physics - just started the upper division stuff, but that's my take so far). For example, in...
Consider F(t) = sin(wt) when 0 < t < pi/w and 0 when pi/w < t < 2pi/w. Where w is the frequency and t is the time. Find the Fourier Series
F(t) = sum of (ck e^ikt)
See attached doc with math type; its a lot more readable.
A pendulum is suspended from the cusp of a cycloid cut in a rigid support. The path described by the pendulum bob is cycloidal and given by
x = a(phi – sin(phi)) y = a(cos(phi) – 1)
where the length of the pendulum is l = 4a, and where phi is the angle of rotation...
x(t) = x1 * [r(t) – r] = x1 * (½ at^2 + vt)
= x1 * ½ at^2 + x1 * vt (since a not || v, then v not perpendicular to x)
= 0 + |x1||v|cos(theta) = vtcos(theta) where v is now a scalar
y(t) = (½ at^2 + vt)cos(theta)
So now do I do this… ½ at^2 + vt = B (vt)^2...
Hi, got my HW back from prof. There were a few problems... I want to understand these before the test.
Show that r(t) = (at^2)/2 + vt + r lies in a plane and that if a and v are not parallel, then r(t) traces out a parabola. Note a, v, and r are constant vectors here...