How do I convert gph to psi?....
Here is the deal, we are testing a 24" pipe for leaks doing a pressure test. the pressure at the pipe in question is 185 psi, and it lost 4 psi. I have a chart showing the allowable loss in GPH, but I dont know how to convert to PSI. Since this was a test...
1.I am given a zenith angle of 73 (degrees) 17'30"
2. How do I compute (2360/5280)times cos(73 degrees, 17'30") with a ti 89 and a regular scientific calculator?
3. The solution is .446 degrees
Thank you sooo very much.
http://wps.prenhall.com/wps/media/objects/3076/3149958/studypak/questions/html/Ch16/9e_16_43.html
That is the image of the problem, which includes a solution. PROBLEM- Besides being really confused on their work, the solution they give and the solution in the back of my book are both...
http://wps.prenhall.com/wps/media/objects/3076/3149958/studypak/questions/html/Ch16/9e_16_43.html
That is the image of the problem, which includes a solution. PROBLEM- Besides being really confused on their work, the solution they give and the solution in the back of my book are both...
thank you both very much.
Mindscrape: The difference is that the ball has tangental and normal acceleration components, however using energy they should both come out to be the same speed, because neither of them ever stops. but because their acceleration and velocity vectors are so...
Learning physics: The velocity is the same at impact because the vx component does not change, but what of the Vy component? It makes sense that it doesnt actually increase more than its given velocity.. but not sure why its the EXACT same.
So heres my plan- Ill set up the energy equation...
The ball is fired with an intial velocity of 10 m/s up a smooth inclined plane. The planes dimensions are 1.5 m high and 2 m long on the bottom so the hypotenuse of the plane is sqrt (1.5^2+2^2). It has enough velocity to make a parabolic shape as it is coming off the plane. .. Confusing I know.
Homework Statement
the 2 kg ball is fired from point a with an Vo of 10 m/s up the smooth inclined plane. The angle is 37 degrees, it gives me the planes dimentions the ball rolls on, it is 1.5 m high and 2 m wide. It asks the distance in the x it lands. Also the velocity with which it...
yes, i redid everything as maximum speed and got 118.8.
i found the power dissapated= 325*30m/s divded by 550 to convert and got 17.7 HP. Then I found the max energy using the max velocity as 1/2mv^2, converted it to power- 101.6 HP, added both since the power dissipated will need to be...
me too. Im wondering if the Pmax eq is different, I remember from physics it being slightly different but I cant find a difference.. I have the answer already, it should be 119 HP.
thanks for the reply. But your going to have to spell it out for me as I have tried everything known to man.
what does the total energy have to do with it?
I know the mass, times the acceleration found through kinematics, and the fictional force is 375, add it all together to get the total...
Homework Statement
A loaded truck weighs 16*10^3 lb and accelerates uniformly on a level road from 15ft/s to 30 ft/s during 4 s. If the frictional resistance is 325 lb determine the max power delivered to the wheels.
Homework Equations
I already know the answer, its 119 HP but I dont...
Solve y'= Ln(12x)
Homework Equations
Integral of ln(x)= xlnx-x dx
The Attempt at a Solution
12x*ln(12x)-12x dx or even xlnx-x*1/12
But Im pretty sure these are wrong.
My calculator gives me xlnx+(ln(12)-1)x wth? Help!
"If any portion of the function goes to infinity, no finite number can be a global maximum!"
I dont think thats true. X^2 has a global min, even if it does goto infinity.
yes! The problem is, Evlaute that integral by changing the order of integration. Im wondering if I should just switch the dy , dy limits and integrate or if I do that will i need to change my limits. AND, on top of that, Im doubting my integration skills on this problem. *sigh* thanks for...
I am sure it is is x^2 in the parenthesis.
So when I solved for z I got z=(2cos(x^2))^(1/2).
Thats right, right?
I graph this and get a cos function parralel to the y axis.
Since my dx limits are 2y and 2, i can graph 2y and 2 on a 2 D graph and see how it would be on the 3D graph. my Dy...
I said, the function does not have any bounds so it does not have a global max.
I graphed the function with my handy dandy computer graphing program and it
looks like it could have a global max in the positive x/y region although a portion of the function does goto infinity.
?
Homework Statement
Evaluate the integral 4cos(x^2)/ (2((z)^(1/2))) dxdydz, limits for x 2y to 2, for y, 0 to 1 and for z 01, by changing the order of integration.
Homework Equations
Would I need to change the limits in order to accurately change the order of the integration? Im...
Heres the question:
Consider the function fxy= x+y+9/x+1/y. Determine all the local max min and saddle points. DOes f have any global maximum points in the region R where x,y>0 Explain algebraically.
So I found only one critical point, 3,1 and found it to be a local min.
As for the global...
well i get the same answer taking the integral of the lower plane completely and integral of upper plane completely, setting my dy=2-x both times, subtracting two answer= 2.
then i did a integral subtracting both the planes, y=2-x, x=0..2 and got 2 again.
Im supposed to do a triple integral. Are you saying I should do for dz a integral from O to lower plane - a integral from o to highest... Should I compute for y and x for each of those integrals seperately and subtract two different answers?
Does this Fxy have a global Min?
Heres the question:
Consider the function fxy= x+y+9/x+1/y. Determine all the local max min and saddle points. DOes f have any global maximum points in the region R where x,y>0 Explain algebraically.
So I found only one critical point, 3,1 and found it...
Finding Volume between Two planes "Help"
Ok heres the question
Find the volume of the region between places x+y+2z=2 and 2x+2y+z=4 in THE FIRST QUADRANT, using rectangular coordinates.
What I have done:
Graphed the planes. Created x=o y=o and z=o planes to remain in first quadrant for...