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  1. A

    Solubility Product, finding molar concentration

    So the only situation the 2:1 ratio applies is if I was trying to find moles?
  2. A

    Solubility Product, finding molar concentration

    Homework Statement If the 2.0 x 10-5 mol of Cu(IO3)2 can dissolve in 2 L of NaIO3, find the molar concentration of the NaIO3 solution. Ksp = 1.4 x 10-7 for Cu(IO3)2. Homework Equations The Attempt at a Solution Let y = [IO3-(aq)] present in the solution from NaIO3 Cu(IO3)2(s) ↔...
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    PH for this Weak Acid-Strong Base titration.

    0.029+x? Oh I see H_{}C_{2}H_{3}O_{2} + H_{2}O \leftrightharpoons H_{3}O + C_{2}H_{3}O_{2}^{-} I \:\: 0.043 \:\:\:\:\:\: - \:\:\:\:\:\:\:\:\:\:\:\: 0 \:\:\:\:\:\:\:\:\:\:\:\: 0.029 C \:\:\:\:\:\: -x...
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    PH for this Weak Acid-Strong Base titration.

    Thanks for the reply. The other approach is where they use a mole chart like this I just want to know the situations of when to use a mole chart. This had been confusing me for weeks haha.
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    PH for this Weak Acid-Strong Base titration.

    \:Homework Statement What is the pH when 10 ml of 0.1 M NaOH is added to 25 ml of 0.1 M H_{}C_{2}H_{3}O_{2}? Homework Equations pH = -log[H_{3}O] The Attempt at a Solution The main thing confusing me about this type of problem is that my teacher taught me a way which is different from the...
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    Getting N-methyl-2-aminobutane from 2-aminobutane

    Homework Statement draw structural equation for going from 2-aminobutane to N-methyl-2-aminobutane Homework Equations The Attempt at a Solution CH3=CH-CH2-CH3 + CH4 ----> CH3-CH-CH2-CH3 | | NH2 CH3-NH2 It...
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    Some confusion with c1v1 = c2v2

    Homework Statement Determine how much distilled water must be added to 250 ml of a 1.5 M solution of Na2CO3 to dilute it to a concentraion of 0.5 M. Homework Equations c1v1=c2v2 The Attempt at a Solution I'm having trouble understanding how to identify c1,v1,c2, and v2, especially since...
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    Finding volume of a solution using %W/V

    Homework Statement What volume of a 30% W/V hydrogen peroxide solution is required to prepare 425 mL of a 6.0% W/V solution? Homework Equations %w/v = (weight solute/volume solution) x 100% The Attempt at a Solution I'm not quite sure what to do because here I am given 2 percentages...
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