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  1. K

    The Forces of Rolling

    The question is: A wheel is rolling smoothly on horizontal surface. There is a constant horizontal force of magnitude 10 N. Wheel has mass of 10 kg, and radius of 0.3 m. The accel. of its centre of mass has mag. of 0.6 m/s^2. I am asked to find frictional force in unit-vector notation. This...
  2. K

    Net Ionic Equation clarification

    I obtained a net ionic equn' as follows Ba +2 (aq) + SO4 2- (aq) ----> BaSO4 (s) Now I need clarification for the following question and my answer to it. What is the max amount of solid product that could be obtained by reacting one mole of each reactant? I believe that b/c of the...
  3. K

    Car Question

    Car Question !!! Two Jeeps P and B race along straight lines, across flat terrain, and past stationary border guard A. Relative to the guard, B travels at a constant speed of 20.0 m/s at the angle theta=30.0*. Relative to the guard, P has accelerated from rest at a constant rate of 0.400 m/s^2...
  4. K

    Help with Stoichiometry and Volumetric Analysis

    I need some help with this question. A piece of chalk (mainly calcium carbonate) is placed in 250 mL of 0.293 M HCl. All the CaCO3 reacts, realising CO2 gas, and leaving a clear solution. 50.00 mL of the solution is pipetted into another flask. 87.1 mL of 0.0567 M NaOH is required to titrate...
  5. K

    Standardization of An Acid

    Don't worry about it, I figured it out :D
  6. K

    Standardization of An Acid

    So for a I know that M (molarity) = moles of solute/liters of sol'n
  7. K

    Standardization of An Acid

    It requires 46.5 mL of 0.215M NaOH to neutralize 15.0 mL of aqueous H2SO4. What was the molarity (M) of the acid sample? I'm not quite sure how to approach this quesiton, if anyone has and starter tips please let me know.
  8. K

    The acceleration of a particle on a horizontal xy plane

    alright so i got: dx = 1.5t^2 + vcos0t + 20 dy = 2t^2 + vsin0t + 40 where the 0 is theta
  9. K

    The acceleration of a particle on a horizontal xy plane

    so would i integrate a to find position and then velocity?
  10. K

    The acceleration of a particle on a horizontal xy plane

    The acceleration of a particle on a horizontal xy plane is given by a=3ti + 4tj, where a is in meters per second-squared and t is in sec. At t=0, the particle has the position vector r=(20.0m)i + (40.0m)j and the velocity vector v=(5.00m/s)i +(2.00m/s)j. At t=4.00 s, what are its position...
  11. K

    Basic Physics Volcano Question

    During volcanic eruptions, chunks of solid rock can be blasted out of the volcano; these projectiles are called volcanic bombs. At what initial speed would a bomb have to be ejected, at angle 35* to the horizontal, from the vent at A in order to fall at the foot of the volcano at B, at vertical...
  12. K

    Basics Physics VECTOR Question

    The acceleration of a particle on a horizontal xy plane is given by a=3ti + 4tj, where a is in meters per second-squared and t is in sec. At t=0, the particle has the position vector r=(20.0m)i + (40.0m)j and the velocity vector v=(5.00m/s)i +(2.00m/s)j. At t=4.00 s, what are its position...
  13. K

    Basic Physics Question please help

    if i multiply both sides by 2 to get rid of the 1/2 i get 106 = -(9.8) t^2
  14. K

    Basic Physics Question please help

    i plugged in all my values but get stuck at one point with a negative square root: 53 = -1/2(9.8)t^2
  15. K

    Basic Physics Question please help

    well the max height is 53 m, and it reaches that height when v = 0.0 m/s
  16. K

    Basic Physics Question please help

    so i can solve for t in the y=y0 + v0-1/2gt^2 equation and sub t into x=x0 +v0t equation and solve for x
  17. K

    Basic Physics Question please help

    and b/c im looking for how far its been displaced horizontally from the launch pt. i am looking for x?
  18. K

    Basic Physics Question please help

    Now i have to calculate how far is its displacement horizontally from launch pt, at the instant it achieves max height. So i know that its v will be 0 m/s at max heigh.
  19. K

    Basic Physics Question please help

    So the horizontal component of my initial velocity is 20 m/s, and the vertical component of initial velocity is 36.6 m/s
  20. K

    Basic Physics Question please help

    Alright, so i got 36.3 m/s for v0
  21. K

    Basic Physics Question please help

    :O I just figured something out... Don't know if im on the right track but let me know: If i solve for v0 in equation x=x0 + v0t, then i can sub that into the other equation?
  22. K

    Basic Physics Question please help

    alright so solving that equation would give me v0. Now what do i do with that? would i also need to solve for v0 in equation x=x0 + v0t?
  23. K

    Basic Physics Question please help

    you said i left out the vertical displacement at time, so that would be y in the case of this equation y = y0 + v0y*t - 1/2*g*t^2 , and y is 53 m ?
  24. K

    Basic Physics Question please help

    you said i left out the vertical displacement at time, so that would be y in the case of this equation y = y0 + v0y*t - 1/2*g*t^2 , and y is 53 m ?
  25. K

    Basic Physics Question please help

    so all the - demonstrates is the negative direction?
  26. K

    Basic Physics Question please help

    its on the ground?
  27. K

    Basic Physics Question please help

    wait.. wouldn't gravity be -9.8 m/s^2 so that the answer would be 19.6 ??? and i don't know what units it'd be
  28. K

    Basic Physics Question please help

    so: - initial position (y0) would be 0 m - initial velocity (v0) would be 0 m/s - time would be 2.0 sec - force of gravity 9.8 m/s^2 so my answer would be -19.6 m/s??
  29. K

    Basic Physics Question please help

    y = y0 + v0y*t - 1/2*g*t^2 ?
  30. K

    Basic Physics Question please help

    now how do i find vertical component?
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