Solve y' = y/x + 1/y
I get a similar answer to the correct one but I believe I am making a substitution error. Here is my attempt:
dy/dx = y/x + 1/y
set v = y/x
equation now becomes: v + x(dv/dx) = v + 1/(x*v)
reduces to: dv/dx = 1/(x^2 * v)
Now the equation is...
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