Hi and thanks for your answer. Ok, i just realize i have been too vague.
Acutally my expressions are of the type
MP[X,a_1]...MP[X,a_{2n}] where MP is the Minkowski scalar product. Some of the a_n might be the some. This can be replaced in my case (under an integral over X) by...
Hi guys,
i have expressions of the type (X*a)(X*b). I want replace this by X^2(a*b).
So i tried building a block which does nothing but
%//.(X*a_)(X*b_)->X^2(a*b).
However, this works only if a is distinct from b. If a and b are equal if HAVE to use the replacement command...
Hi again!
Hm, you are right.
What I forgot to write, is that I (or precisely the guys in the paper) am/are doing a Taylor expansion of the solution the zeros of the denominator in epsilon and evaluate the residues at the Taylor expanded expression. In that sense "my" epsilon (after Taylor...
Hi, thanks for the answer :)
The poles of the denominator are located at
x^\pm= \frac{B \pm \sqrt{d} \mp i \epsilon }{A}
and i want to evaluate the residues at x^- .
So i type into Mathematica
Residue[...
Thanks for the reply!
Ok, if I enter a function (a similar one, to be more specific but the core question remains) in its original form
\frac{(Q*X+q*x)}{((x-B/A)^2-(B^2-AC)/A^2+i\frac{\epsilon}{A})^3}
Mathematica gives me as the residue zero. But I know (from calculating it...
Hey guys,
i have the following situation:
I have a function which looks like
\frac{(a+bx)^3}{(x-y)^6(x-z)^6}
As one can easily see this function has poles at y and z of order 6. Now, I know how to calculate the residue of this function for instance at y, but how do I implement this into...