Um, a^2 = b^2 + c^2 is the same thing as the formula I posted...
But, either way, yout idea is not right. 141.7 million is the mean distance not the distance to any point on the orbit. I think the sun is supposed to be at the focus.
Having trouble with this problem.
"The mean distance from the sun to Mars is 141.7 million miles. If the eccentricity of the orbit of Mars is .093, determine the maximum distance that Mars orbits from the sun."
So basically what it is asking for is half the length of the major axis right...
I don't want coordinates for when the value equals 0. All I want, is to convert the rectangular equation into polar form. So instead of having x and y I need r and \Theta.
Currently, I have r^2-3cos\Theta+4sin\Theta=0 but I don't know how to convert the sin and cos into polar form.
I have to find (a+bi)(c+di) in polar form given that b,c,d>0 and a<0.
So I convert each one to polar first.
( (a+b)cis(\arctan(-b/a) + \pi) ) ( (c+d)cis(\arctan(d/c)) )
That's as far as I got. Little help please?
Yeah, I figured out the tan(x) thing. These were due today. I forget how I did the 2nd one because I didn't do it like you said. It worked some other way. What is the purpose of learning precal when the calculator already told me the answer :p
Oh, my teacher told me sin and cos usually mess things up, but I guess that is the only option.
I ended up with 2sin(x)^2 - 2cos(x)^2 + 3cox(x)sin(x) = 0 for the first one. That can't be right can it?
And using the identity on the 2nd one I get:
-sin(x)^2 + sin(x) +1 = 0
I'm having trouble with two problems:
2tan(x) - 2cot(x) = -3
cos(x)^2 + sin(x) = 0
On the 2nd one, I can substitute 1-sin(x)^2 for cos(x)^2 right? I tried that, but it didn't work. And I have no clue what to do on the first one. Little help please?