# Search results

1. ### Ellipse Word Problem

Oh, I figured it out. Turns out that 141.7 = a . So then using the eccentricity I solved for c and then for b using the relationship between the 3. Then the max is a + c and the min is b - c. :)
2. ### Ellipse Word Problem

Oh, I took the square root to get that. Anyways, what am I suppsed to do then?
3. ### Ellipse Word Problem

OK, so .093 = 1 - \frac{b}{a} and .093^2 = 1 - \frac{b^2}{a^2} But if I rewrite the first I get a = .093a+b That can't be right because I still have 2 variables.
4. ### Ellipse Word Problem

Yeah, I still don't know why that person said that >_>
5. ### Ellipse Word Problem

So what you're saying is that: .093 = \sqrt{1 - \frac{b^2}{a^2}} and .093^2 = 1 - \frac{b^2}{a^2} Right?
6. ### Ellipse Word Problem

Um, a^2 = b^2 + c^2 is the same thing as the formula I posted... But, either way, yout idea is not right. 141.7 million is the mean distance not the distance to any point on the orbit. I think the sun is supposed to be at the focus.
7. ### Ellipse Word Problem

Yeah c^2 = a^2 - b^2
8. ### Ellipse Word Problem

But there is 3 variables...right?
9. ### Ellipse Word Problem

Having trouble with this problem. "The mean distance from the sun to Mars is 141.7 million miles. If the eccentricity of the orbit of Mars is .093, determine the maximum distance that Mars orbits from the sun." So basically what it is asking for is half the length of the major axis right...
10. ### Rectangular Equation to Polar

Yes it does. So what do I do next?
11. ### Rectangular Equation to Polar

I don't want coordinates for when the value equals 0. All I want, is to convert the rectangular equation into polar form. So instead of having x and y I need r and \Theta. Currently, I have r^2-3cos\Theta+4sin\Theta=0 but I don't know how to convert the sin and cos into polar form.
12. ### Rectangular Equation to Polar

Well, actually, I guess they are the same thing, but either way, I don't know how to do it :( As for your question, I don't see a purpose, but my teacher sure does.
13. ### Rectangular Equation to Polar

Who said anything about coordinates. The polar form of the equation is what I need to achieve.
14. ### Rectangular Equation to Polar

I need to convert x^2+y^2-3cos\Theta+4sin\Theta=0 to polar. Obviously the x^2+y^2 part would = r^2, but how can I get the cos and sin part to simplify?
15. ### Imaginary multiplication with answer to be in polar (variables)

That would give -(ac) -(adi) +(bci) -(bd)? But how do I find a modulus and argument with that?
16. ### Imaginary multiplication with answer to be in polar (variables)

I have to find (a+bi)(c+di) in polar form given that b,c,d>0 and a<0. So I convert each one to polar first. ( (a+b)cis(\arctan(-b/a) + \pi) ) ( (c+d)cis(\arctan(d/c)) ) That's as far as I got. Little help please?
17. ### Trigonometric Equations

Yeah, I figured out the tan(x) thing. These were due today. I forget how I did the 2nd one because I didn't do it like you said. It worked some other way. What is the purpose of learning precal when the calculator already told me the answer :p
18. ### Trigonometric Equations

Um HallsofIvy how was the 3 seemingly unaffected by you multiplying through by sin and cos? And when I type in sin^-1(+/- root 5 / 2) I get domain error.... ? What do you mean by let y=sin(x)?
19. ### Trigonometric Equations

Oh, my teacher told me sin and cos usually mess things up, but I guess that is the only option. Edit: I ended up with 2sin(x)^2 - 2cos(x)^2 + 3cox(x)sin(x) = 0 for the first one. That can't be right can it? And using the identity on the 2nd one I get: -sin(x)^2 + sin(x) +1 = 0 Then what...
20. ### Trigonometric Equations

I'm having trouble with two problems: 2tan(x) - 2cot(x) = -3 and cos(x)^2 + sin(x) = 0 On the 2nd one, I can substitute 1-sin(x)^2 for cos(x)^2 right? I tried that, but it didn't work. And I have no clue what to do on the first one. Little help please?