Yes, it is a talking book haha. (Don't know how to do that quote thing you did)
Correct me if I am wrong but because the current source is the load, I thought I just turn it into an open circuit then solve for resistance from there.
I could just be not understand the whole process...
Homework Statement
Problem located in attachment.
Homework Equations
Parallel, series and wheatstone bridge equations for resistors
The Attempt at a Solution
Converted the circuit to look less confusing. Work shown in other attachment.
I am simply using the equations relating to simplifying...
Homework Statement
Determine Vy in the circuit of the below figure:
(In attachment)
Homework Equations
ohms law
resistance adding equations for parallel and series
The Attempt at a Solution
So I found Vx=(1.2A)(5ohms) = 6v
Afterwards I computed the current supplier: (6)(0.1)=0.6...