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  1. A

    Neutron collides elastically with a helium nucleus

    Should it be v1 = 5.05e5 + 16v2? (v1^2) = (v1x)^2 + (v1y)^2 (v1^2) = { (383022.2216 - (4)(v2) }^2 + ( 321393.8048)^2 (v1^2) = (1.4671e11 - 16v2^2 + 1.0329e11) (v1^2) = 2.50e11 - 16v2^2 (v1) = 5.0e5 - 4v2)
  2. A

    Neutron collides elastically with a helium nucleus

    "neutron collides elastically with a helium nucleus" Homework Statement A neutron collides elastically with a helium nucleus (at rest initially) whose mass is four times that of the neutron. The helium nucleus is observed to rebound at an angle θ'2 = 40° from the neutron's initial...
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    Tennis Ball and Impulse!

    So the x and y components are both 30.4. That would be the x component cancels (30.4-30.4) but the y component would double because its going upwards..?
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    Tennis Ball and Impulse!

    same speed, different velocity. But because the angles, speeds, and masses are the same don't they cancel?
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    Tennis Ball and Impulse!

    Is there change in momentum though? Cause its going the same velocity.
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    Tennis Ball and Impulse!

    Homework Statement A tennis ball of mass m = 0.087 kg and speed v = 43 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° (Fig. 7-29). What is the impulse given the wall? Homework Equations Impulse = M x V Sin (theta) = opp/hyp The Attempt at a Solution...
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    Finding coefficient of friction.

    I think i GOT the force required to go up the mountain. Can someone please verify? Fa - Ff - F// = 0 Fa - umgsin(theta) - mgsin(theta) = 0 Solve for Fa.
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    Finding coefficient of friction.

    For the force required to go up the hill is it Fa - Ff = FN Facos(theta) - umgcos(theta) = mgsin(theta)
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    Finding coefficient of friction.

    Ok, so the coefficient of velocity is tangent to the path. That makes sense.
  10. A

    Finding coefficient of friction.

    umg = mgsin(theta ?
  11. A

    Finding coefficient of friction.

    Ok, the question as written is: Question: A bicyclist is traveling down a hill which has a 9.75 degree incline at a constant velocity of 5.95m/s. The mass of the cyclist and bike combined is 98.7kilograms. - What is the coefficient of friction of the surface the biker is traveling on...
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    Finding coefficient of friction.

    Sorry, my bad I re-wrote the question without it in front of me. It is going Down and it asks for the rest when it goes up. But how do i find the coefficient?
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    Finding coefficient of friction.

    Nasu, no i am not given an Fa. All I have is: A biker rides up an 9.75degree hill at a constant speed of 5.95m/s. The biker and bicycle together have a mass of 98.7kg. Find the coefficient.. What force does the system need to make the biker go up the hill at the same velocity.. What must...
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    Finding coefficient of friction.

    umgcos(theta) - gcos(theta) = 0 That would be a very small number.....
  15. A

    Finding coefficient of friction.

    How do you find the force that is needed to go up the hill at the same velocity?
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    Finding coefficient of friction.

    Is it the tangent of the incline?
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    Finding coefficient of friction.

    Ok.. How do i fund mu though?
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    Finding coefficient of friction.

    A biker going up a hill Mass = 98.7kg Constant velocity = 5.95m/s So there is no acceleration.
  19. A

    Finding coefficient of friction.

    Homework Statement Hello, How do i find coefficient of friction knowing only mass, velocity and incline for a inclined plane? Homework Equations The Attempt at a Solution
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