Find the derivative of F(x)= 3 sq rt of x^3-1
First step I did was changing the Sq RT to (x^3-1)^3/2
Then I solved it by 3/2(X^3-1)^1/2*3X^2
Another problem very similar
F(X)= 3 SQ RT of X^4+3x+2
Step 1 (X^4+3x+2)^3/2
I know how...
Another thing after thinking about it a bit more, when it says Graph it on [-4,4] does it mean that the F(x) equation has to to touch that point? If it does its continous? If it doesn't it does not exist?
Grapher: Graph each function on (-4,4), and identify the point(s) at which the function is not differentiable.
Graph F(X) = (X^2-2x+1)^1/3 on [4,-4] and Identify any points of discontinuity.
The Attempt at a Solution
I plugged in the F(x)...