this wat i did...
(2n+4)!/((2n+4)-3)! = (2/3(n+4)!)/((n+4)-4)!
(2n+4)!/(2n+1)! = (2/3(n+4)!)/(n)!
i dont know wat do do next, im soo stuck, since you cannot cancel any of them, so should i cross multiply it?
i cannot get the question since i dont know how to play baseball...
this is the question...
The manager of a baseball team has picked the nine players for the starting lineup. In how many ways canhe set the batting order so that the pitcher bats last?
i just want to confirm if my anser is right....
this is the problem:
solve the expression for n Є N
P(2n + 4, 3) = 2/3P(n+4, 4)
this is my work:
(2n +4)!/(n-3)! = (2/3(n+4)!)/(n-4)!
-2(n-2)!/(n-3)! = -2/3(n-4)!/(n-4)!
-2/(n-3)! = -2/3
-2 = -2/3(n-3)
-2 = -2n/3 +6/3
-2 = -2n/3...