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  1. R

    Intensity of natural light after polarization

    Thanks, this made it clear.
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    Intensity of natural light after polarization

    I read that if a beam of unpolarized light goes through a polarizer, the intensity of the polarized beam is equal to half the intensity of the original beam. Can someone explain me why? I thought the intensity would be the same.
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    Theory of small oscilations

    Homework Statement (see pic) \frac{l_{2}}{l_{1}} = \frac{1}{4} \frac{g}{l_{1}} = 1 I need to find the normal modes of oscillation. (for small oscillations) The Attempt at a Solution I solved the problem using the matricial way and got the following matrix: (I simplified it using the...
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    Classical mechanics

    Ayo everybody, I'm doing a problem about theory of small oscilatons (see pic) and I got the following for potential energy: V= mg(\frac{l_{2}}{2} +\frac{l_{1}}{2} \theta^{2}_{1} + \frac{l_{2}}{4} \theta^{2}_{2}) (after the aproximation cos \theta ~ 1 - \frac{\theta^{2}}{2} Knowing that V...
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    Transmission of light and velocity of light

    Hi ! I think part of the wave energy is transferred to the air particles and as Compton showed the wave length of the wave is reduced after that energy is transferred, and by the formula v= λ * ƒ it's clear why the velocity is lower than in vacuum. I'm not sure if this is the right...
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    Determine the wave function of the particle

    Hi Simon Bridge, thank you for your reply. I did write psiII as a sum of complex exponentials and I got the following: \frac{B}{A} = \frac{\frac{k}{l}e^(ika-ila)-\frac{k}{l}e^(-ika + ila) - e^(-ika -ila) - e^(-ika + ila)}{\frac{k}{l}e^(ika-ila) - \frac{k}{l}e^(ika+ila) +e^(ika+ila) +...
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    Determine the wave function of the particle

    Homework Statement A particle coming from +∞ with energy E colides with a potential of the form: V = ∞ , x<0 (III) V = -V0 , 0<x<a (II) V = 0, x>a (I) a) Determine the wave function of the particle considering that the amplitude of the incident wave is A. Writting the amplitude of the...
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    Infinite potential

    Potential and wave function If a particle comes from +infinite and collides with a potential of the form : V = ∞ , x < 0 (I) -V0 , 0<x<a (II) 0 , x≥a (III) Is the wave function for region (I) = 0? And for region (II) = A sin(kx) with k constant? Really need to...
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    Cosmic simulation software

    Thanks, I'v installed Universe Sandbox and it's really cool .
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    Cosmic simulation software

    Hey, does anyone know what software is used on the astrophysics videos made by NASA? Or similar modeling software where I can play around a bit creating solar systems and stuff like that? Thanks
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    Bar suspended by rope kinetic energy

    Ok I understood that, but my question still remains, (see pic attached in this post) in this case, I know the answer for kinetic energy is T = \frac{1}{2} \dot{\theta}^2 \frac{m L^2}{3} = \dot{\theta}^2 \frac{m L^2}{6} But, according to this statement "The total kinetic energy is given by...
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    Bar suspended by rope kinetic energy

    Ok I already know the answer is I = \frac{m L ^2}{12} . But there's something else bothering me, if there were no rope, only the bar fixed at its beginning (origin) and oscillating in a 2D plane, then the kinetic energy would be only in rotational motion calculated using I = \frac{m L ^2}{3} ...
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    Bar suspended by rope kinetic energy

    I have added a picture to the original post. Ok so T = \frac{ m v_{centerofmass}^2}{2} + \frac{I w^2}{2} So now I still don't know if I should use I = \frac {m L^2}{12} (rotation about the center of mass) or I = \frac {m L^2}{3} (rotation at the beginning of the bar)
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    Bar suspended by rope kinetic energy

    Also sorry for that doublepost, didn't meant to.
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    Bar suspended by rope kinetic energy

    If I needed to calculate the kinetic energy of a bar suspended by a rope at one of its ends, in other words, a bar pendulum, do I need to calculate the kinetic energy of the center of mass plus the kinetic energy relatively to the center of mass or do I need to calculate the kinetic energy of...
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    Is Natural Mathematical Ability Required To Be A Physicist?

    if you cut the belief inside you that you aren't naturally good at math, maybe then you could be naturally good at math
  17. R

    Linearly changing density

    Homework Statement I need to find the Kinetic energy of a bar rotating about its center of mass. I know the bar as length 3b and it's center of mass is located at 2b, the bar density changes linearly along it's length. Homework Equations T=1/2 W^2 I The Attempt at a Solution...
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    Potential well

    1D infinitely deep well. I'll try to do some calculations on my own now. Thank you, have a good night(or day) sir.
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    Potential well

    i) I meant square root, sorry. I don't know where the hell I got that 1/9 for the probability from, it should be 1/10 yes. ii) yes you are right , that means what? there are 250 particles on each half? Thank you for the help so far.
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    Potential well

    i) the squares of 1/9 and 9/10, which are the probabilities of a particle having energy 4E1 or 225E1. ii) I just have to integrate (3) with the limits a/2 and a, no?
  21. R

    Potential well

    Homework Statement At the instant t=0, there's a system with 1000 particles in a box of length a. It is known that 100 have energy 4E1 and 900 have energy 225E1, where E1 is the energy of the fundamental state. i) Build a wave function that can represent the state of a particle ii) How many...
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    Angular moment cube

    Its just the result of the L vector norm : w\sqrt{(\frac{5Ma^2}{3\sqrt{2}})^2+ (\frac{-2Ma^2}{\sqrt{2}}) ^2 +(\frac{5Ma^2}{3\sqrt{2}})^2}=\frac{\sqrt{43}Ma^2w}{3}
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    Angular moment cube

    Sorry for the above post, somehow I managed to post a duplicate reply and now I cant delete it. Using the formulas for the first part of the angular momentum I got: L_{x}=\frac{2Ma^2}{3\sqrt{2}} L_{y}=0 L_{z}=\frac{2Ma^2}{3\sqrt{2}} for the second part of the equation...
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    Angular moment cube

    you mean like \vec{w} = (cos (\frac{pi}{4}) w ; 0 ; sen(\frac{pi}{4}) w) ? considering that the diagonal which upon the cube rotates is in the xOz plane. I tried that with no success.
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    Angular moment cube

    Homework Statement An homogeneous cube of mass M and side 2a spins around one diagonal of the faces with constant angular velocity w. Show that the size of the angular moment in relation to one of the fixed vertexes is \sqrt{\frac{43}{3}}Ma^2w What I visualize here is a cube with one of its...
  26. R

    Hoop kinetic energy

    T =\frac{1}{2} w^2 \frac{1}{2} M a^2 ? is it more close to the answer now?
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    Hoop kinetic energy

    Hey PF, this is just a quick question: If there's a hoop of mass M and radius a rotating around its vertical axis (see pic) and I want to write the kinetic energy for the Lagrangian is it just T = \frac{1}{2} M a^2 w^2 ? Considering w the angular velocity
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    Capacitor AC

    when d is not << a? but where is the mathematics to show it?
  29. R

    Capacitor AC

    hm no..
  30. R

    Capacitor AC

    E_{0}=\frac{V_{0}}{d} ?
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