# Search results

1. ### Work done on a block

If you lift an object, you are giving it gravitational potential energy. So, to put it at the top of that incline, it will have gained potential energy. When it is released, it is losing potential energy, but gaining gravitational kinetic energy. KE = PE ================== When...
2. ### Resonance in a Wineglass

The length will affect it more than anything; the standing wave that occupies it is determined in large by the length, as this affects the number of nodes that can form.. f=\frac{nv}{4L} n = harmonic [where you can only have odd harmonics [1, 3, 5, etc].] L = length. v = velocity of the wave.
3. ### Momentum Theory question Gr.12

(ms×vs)+(mb×vb) = (ms+mb)v^2 Where: ms = Mass of student vs = Velocity of student mb = Mass of bag vb = Velocity of bag In writing; The sum of the initial momentum (p=mv) on both objects is equal to the final momentum, where the masses are combined. If you have objects moving on angles, you...
4. ### Static friction on a slope.

A block is sliding down a 30° incline at 1.2ms^-2 Find the coefficient of static friction. [g=9.8ms^2] I am stumped.. Some relevant equations: Fr = μ(Fn) Fn = mg Ultimately I got μ=0.5 ---> This was through mashing and playing with some trig.
5. ### Springs: Speed when released & distance traveled.

This gave me the same result [5cm, 0.05m] as one of the ways I tried it originally: [v^2 = u^2 + 2ad] Where: a = F/m = 4N / 1.6kg = 2.5ms^-2 v = 0.5ms^-1 u = 0ms^-1 (0.5)^2 = (0) + 2 (2.5) d 0.25 = 5d d = 0.25/5 d = 0.05m [5cm] -------------------------------------------------...
6. ### Springs: Speed when released & distance traveled.

-------------------------------- Question: -------------------------------- A 1.6 kg block is pushed into a spring with spring constant of 1.0 x 10^3 N/m. The spring is compressed a distance of 2.0 cm [0.02m], and the block is released from rest in the horizontal direction. (a) Calculate...