Search results

  1. I

    Thickness of lead required for 200 keV x-rays?

    I found that factor online.It said to get intensity to < 1% but by my calculations, for 200 KeV beam using formula: HVL = 0.693/u need 7 HVL layers to get to 0.8% which is 4.48 mm. where u = 10.15 cm^-1
  2. I

    Thickness of lead required for 200 keV x-rays?

    is this correct? mass attenuation coeff. = 8.636 cm^2/g 8.636 * (density of lead: 11.3 g/cm^3) = 975.868 per cm thickness (mm): t= 9.21 / 975.868 = 0.009 cm = 0.09 mm
  3. I

    Electron in magnetic field equation

    equation for radius of curvature of relativistic electron in magnetic field? is this correct: R = gamma * m * v / e * B where gamma is lorentz factor, m is electron mass, v is velocity, e is electron charge and B is magnetic field strength.
Top