My friend provided me with the teaching materials from a course he took. The assignment of fingers is switched around. B is the middle finger, F thumb and I index finger.
As long as it yields the same result, there's no harm done!
Thanks a million for guiding me along so generously. I'm really...
ok, so, index finger(particles) on the +x-axis, thumb (magnetic field) on +y-axis, so magnetic force is actually "into the paper", i.e. the positive z-axis?
I will need some sort of hand massage after this ;)
my reply got deleted as I wasn't logged in properly...
the electric field, like the magnetic force should be perpendicular to the magnetic field.
I used your formula blue_leaf77 for the calculations. I think I actually need to use the right hand rule to determine the direction?
That gave me a...
beam of protons moving in +x direction at speed v
electric field is perpendicular to magnetic field
magnetic field in +y direction
What direction/sign has the electric field?
not looking for numerical solutions
The Attempt at a Solution...
exactly. Very often relationships are messy in so many ways and do not provide the happiness, security and unconditional love one should get out of it. While that may not what everybody is looking for in a relationship, why would you settle for anything but the best?
That sounds promising :) So...
From my experience a lot of people your age feel exactly like you. As has been said, there is a prevalent tendency to overstate the intimacy/happiness and number of relationships(friends and partners) - most people don't want to appear to be a loner.
If you can't afford your own place, maybe...
ok, dot product would be
=Px*Qx + Py*Qy + Pz*Qz using the cartesian coordinates, correct?
for c) that would be
for P: Sqrt(2^2+3^2)
for Q: SQRT( 4^2+6^2)
I'll have another look at e) later.
Thanks so much this really helped already.
I think I have to read up more on unit vectors...
Oh my, right, that was silly.
It should be like so, right?
sqrt( (Px - Qx)^2 + (Py - Qy)^2 + (Pz - Qz)^2 )
would you please comment on part a) and b) as well?
you are so right, WrongMan! Thanks for that.
so if I'm not mistaken:
With all lenghts of an imaginary triangle...
Hi this isn't my homework, but it is taken from a worksheet for a Maths course(trying to refresh my rusty math), so I hope it fits in here.
1. Homework Statement
two cylindrical polar vectors with same origin:
P(2,55°,3); Q(4,25°,6) units in m
a) Express in cartesian...