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1. ### Acceleration of elevator and force in cable

Thanks for your help! Got there in the end...
2. ### Acceleration of elevator and force in cable

(m1*a) + (m1*g) - C1 = C2 (500 * 0.85) + (500 * 9.81) - 1200 = 4.13kN Is this correct taking all variables into account?
3. ### Acceleration of elevator and force in cable

Is it as simple as doing F=ma, f=500*0.85, giving me an answer of 0.425kN. Or do I need to take the 1.2 kN and weight of the elevator into account as well?
4. ### Acceleration of elevator and force in cable

They are connected through the same pulley therefore will have the same velocity and acceleration. Which would mean the acceleration of the elevator is the same as the counter block... Is that the logic you were trying to make me realise?
5. ### Acceleration of elevator and force in cable

Units are in m/s^2 for acceleration? The elevator car will be moving upwards as the counterweight is moving down, I'm not sure what this suggests about the acceleration..
6. ### Acceleration of elevator and force in cable

Disregarding C2. The acceleration on the counterweight alone is: F=ma a = F/ m a = (1314N - 1200N) / 134 a = 0.85 ??
7. ### Acceleration of elevator and force in cable

I am confused now as to whether or not I have used C2 in the right application?
8. ### Acceleration of elevator and force in cable

The counterweight has a force of 1.314kN acting downwards and 1.2 kN acting upwards. Therefore the counterweight is going down and pulling the elevator upwards?
9. ### Acceleration of elevator and force in cable

Homework Statement Mass of elevator = 500kg Counterweight = 134kg Force in cable C1 is 1.2kn Determine the acceleration of the elevator and the force in cable C2 Homework Equations The Attempt at a Solution a = f / m a = (C2 - C1) / m2 a = ((m2 * g) - C1) / m2 a = ((134 * 9.81) -...
10. ### Statics Questions - Equilibrium in a pulley system

Am I right in thinking the forces are acting like this?
11. ### Statics Questions - Equilibrium in a pulley system

Homework Statement Find the value of W to maintain equilibrium Homework Equations The Attempt at a Solution I have split the system into two, creating a triangle. From this I have a right angle triangle with an adjacent of 2m, opposite of 0.6m and an hypotenuse of 2.088m (calculated through...