Homework Statement
OK we had a lab and the lab was to draw some dots mapping a electric field. I connected the dots, but i have no idea which way the field points and how to calculate the electric field. I think we need to use E= dV/dS , but i have no idea what dS is. Do i just take the...
ok im no expert but i got the sign to be 30.4 kg. My class is in the same subject right now. so if you know the answer and it is somewhat similar to mines I can tell you how I did it. I don't want to tell you the wrong thing until the answer is confirmed.
FxsinθL - WcosθL / sin θL = Tension
edit: FxsinθL - WsinθL / sin θL = Tension
then it will simplfy as ,
T = Fx-W = Tension... now it doesn't even seem right
Homework Statement
http://img820.imageshack.us/img820/3505/23625990.jpg [Broken]
Two uniform beams, each of mass M and length L, are connected by a hinge at the top and by a chain of negligible mass attached between their centers. The system will stand upright on a frictionless surface as...
ohh i see it now, thanks you. My class just started this section and I'm kinda new to this. Is there a shortcut of doing this or I have to write out the terms to find power series?
Homework Statement
Represent (1+x)/(1-x) as a power series.
Homework Equations
The Attempt at a Solution
I started with 1/ (1-x) = sum (x)^n n= 0 - infinity
(1 + x) sum x^n
and this is where I am stuck.
Homework Statement
Homework Equations
The Attempt at a Solution
A proton with initial kinetic energy (5.2 MeV) collides with an alpha particle (initially at rest). The collision is perfectly elastic and the proton travels off at an angle of 133o relative to its initial direction. What is the velocity of the alpha particle after the collision? Assume the...
I see it.
Edit: Got it!
angle = 81.07 if I did this right.
[PLAIN]http://img176.imageshack.us/img176/2347/32500903.jpg [Broken]
Picture for who any1 wants to see what I'm doing.
r=(sinB)R , R = 0.1m
T=4rev/sec
V= 4(1 rev)/sec = 4(2(pi)r)/sec
a_rad= v^2/r ...
Ok, I got r=(sinB)R , since the hoop is spinning, the bead will be going up. As it goes up r will will be changing with respect to angle.
where you get this?
Homework Statement
[PLAIN]http://img508.imageshack.us/img508/6861/21296472.jpg [Broken]
I tried to get a_rad and if i didn't make any mistake, then a_rad = 15.79 m/s. I need to find angle when the bean is at vertical equilibrium.
Homework Equations
a_rad= v^2/R =...
Omg you did it!
Mass of B will be 25/9.8=2.55
Mass of C will be (the answer I got from part c), 30.8/9.8=3.14
so with the questions you gave me
w-t=ma and t-f-p=ma
i can t=w-ma and replace t in the 2nd equation
w-ma-f-p=ma, and replacing with what I already know...
N= cos(36.9)(25)
Friction = (cos(36.9)25)(0.35)
Tension = 30.8N
∑F= t-f-n?
So i got 30.8-19.99-6.997=3.813N
and mass is 25/9.8=2.55kg
so in the end i get 3.813=2.55a
a = 1.495m/s^2