# Search results

1. ### Centripetal Acceleration along a curve

No, its not circular when including C,..so does that mean that a=V^2/R doesn't apply in this case? So that means I would simply use a motion equation to determine acceleration? Also, why is mass mentioned in the question? does it have a significance?
2. ### Centripetal Acceleration along a curve

Yes, but in order to find the displacement between A and C, I drew a line connecting the two, forming a right angle triangle. The vertical distance to C was 50m. However, I used the motion equation to find the horizontal distance of the triangle. Then I calculated the hypotenuse to get a...
3. ### Centripetal Acceleration along a curve

I've spent hours on this question: A truck of mass 4500 kg is traveling in a fog due north at 20 m/s. Suddenly, at point A, the driver notices a wall straight ahead. He makes a sharp right turn along path AB, which is one-quarter of a circle of 50 m radius. He does this without any change in...
4. ### Constant Breaking force for roller coaster

Please someone! I need urgent help. I need to know how to do this before tomorrow. I am begging.
5. ### Constant Breaking force for roller coaster

How would I use the Conservation of Energy formula? If the equation is ET=1/2(mass)(Velocity squared) + (mass)(gravity)(height) Would I assume height to be zero? Or would it be 95m? EDIT: I know I would isolate Velocity Squared.
6. ### Constant Breaking force for roller coaster

Yup, I know those equations. I know that first we're going to figure out the distance down the slope. I used the sin law to figure out the length. Then I'm going to use the first kinematic equations (V2=V1+AxT , where V2 equals final velocity, V1 equals initial velocity, A equals...
7. ### Constant Breaking force for roller coaster

I really don't understand this: Consider a frictionless, 12000-kg roller coaster that starts at rest at the top of a hill, point A, 95 m high. It goes all the way the 75 degree steep hill and coasts horizontally (for an unspecified distance) before reaching point B (0 m high). The entire ride...
8. ### Why is the acceleration not equal to 9.81 m/s^2

How am I guessing blindly? I'm asking a question in order to correct a possible mistake, which is pretty natural when learning almost anything. Rather than telling me to see for myself, you can explain a concept I don't understand, because I've made the equation and still don't know why my...
9. ### Why is the acceleration not equal to 9.81 m/s^2

Thanks a lot! But would I be correct to say that in order to find the mass of the puck, I could simply multiply 0.05 kg by 9.8 m/s^2 to get 0.49 N as a force, then divide it by my acceleration. Or would that be the incorrect force? My teacher is forcing us to find the mass by creating...
10. ### Why is the acceleration not equal to 9.81 m/s^2

Homework Statement I'm doing a lab where there is a pulley system. A mass of 50g is attached to a string that goes through the pulley, which is then attached to a puck, on a frictionless air table. So when the mass is let go, the 50g pulls down the puck to the edge of the table. So why...
11. ### Basic projectile question help?

Oh, of course! The velocity of the helicopter would be the initial velocity for the package (but negative). This means I'd first have to find the final velocity (using final velocity^2-initial velocity^2=2xgravityxdisplacement) and then use that to find time (with V2=V1+gravityxtime). I got...
12. ### Basic projectile question help?

Oh, of course! The velocity of the helicopter would be the initial velocity for the package (but negative). This means I'd first have to find the final velocity (using final velocity^2-initial velocity^2=2xgravityxdisplacement) and then use that to find time (with V2=V1+gravityxtime). I got...
13. ### Basic projectile question help?

I know how to do most projectile questions, but if just can't seem to get the correct answer for this: 6) A helicopter is ascending vertically with a velocity of 8.0 m/s at a height of 120 m when a package is dropped out of the door. How much time passes before the package hits the ground...
14. ### When will two football players collide?

I could state a variable, like x, for the distance covered by runner 1, and say that the distance covered by runner 2 is 42m-x. Is that somewhat on the right track? Thanks for helping by the way! Means a lot.
15. ### When will two football players collide?

This is Grade 11 Physics. I don't want the answer, I just want to know how to do it: Two football players separated by 42 m run directly toward each other. Football player #1 starts from rest and accelerates at 2.4 m/s2 [E], and football player #2 moves uniformly at 5.4 m/s [W]. (a) How...