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    Shrinking and Expanding Space?

    Where can I find information on shrinking and expanding space as a form of travel?
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    Where do we go from here?

    And your babbling is why it will never be so.
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    Time Barrier?

    I slipped the word you in there :( That is my mistake sorry. I meant any object or particle or tachyon.
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    Time Barrier?

    Also, that is only taken into effect if the train was moving at near the speed of light.
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    Time Barrier?

    It was purely theoretical, and not to dispute, but your statement is incorrect. Nobody knows if tachyons do in fact exist, and until a credible theory can be raised, faster then light travel or communication cannot be disproved.
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    Time Barrier?

    When an object breaks the sound barrier, sounds "lag" behind that object as it travels faster, theoretically the same can be said for light. Would this work the same for time? If you exceeded whatever limit this barrier has would time "lag" behind you?
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    All possible paths

    A node is a location. For example, if you were planning a trip, you would of course establish a path that would get you to your destination fastest. On a map, each city would represent a node that you may travel into and away from.
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    What is the tension of each wire?

    Neglecting torque, the scaffold's center of mass will be proportionaly distanced in accordance to the tension on each string. This is a rather hairy calculation, so I would advise the use of Doc Al's method if you are familiar with how to calculate torque.
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    Physics Problem

    They will have the same PE in perspective to the point from where they were let roll. Because: PE = {mgy} And therefor, using the top of the ramp as your 0 height. Since Potentical Energy is perspectively based, it will be the same.
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    Asymtotes and polynomials

    They dont occur when F(x) tends to infinity, that is the limit as x approaches positive infinity and as a way to find the Horizontal asymptote. You need to specify the use of only the highest degree terms in the numerator and denominator.
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    Asymtotes and polynomials

    There is an easier method to finding these. It covers basically what was said above but uses more conventional methods. Vertical Asymptote(s): X values that make the denominator zero. Just reverse factor the zero's and you will end with the original equation. Although be careful, with...
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    Quick work question

    Energy is not lost in motion. That is a dissipative force. Energy is never lost, it is transformed into another form. Such as heat, wind resistance, etc.
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    Greatest Integer Problem

    So basically my answer reformatted :biggrin:
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    Purpose of Neutrons and other q's

    Just a little extra note, finding ionized atoms is not very common. Because of octet rule and how it affects the atom. So it is rare to find them in nature.
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    Quick work question

    Power is \frac{work}{time} What you are reading is a calculus based derivative, not relavent to what you are asking.
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    Greatest Integer Problem

    Your book is right. You need two functions because you have two sets of parameters. The first function is (t-1) because of the greatest integer function. Take a call of 5.1 minutes for example. It should be equivalent to a 6 minute call which is 2.48 dollars. Now (5.1-1) = 4.1. The greatest...
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    Initial velocity of the golf ball

    Vectors! Just use vectors for the individuals forces, and make a diagram of them. sin\theta = \frac{Current}{Speed of Boat}
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    Projectile Motion Help!

    In addition to above, the initial velocity would be zero iff you were working with the system inside the cannon barrel. Then the final velocity would be the velocity of the ball when leaving the cannon. Which you could in turn use as your initial velocity for the projectile motion. You can only...
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    Initial velocity of the golf ball

    Is that all the information given? Because that is an impossible problem unless you make an assumption that no matter the angle, the force exerted on the ball would be the same. Hint: The maximum distance will be found when both components of the velocity are equal. Think if you hit the ball...
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    Perfectly Inelastic Collision

    You can use the properties of momentum to calculate this, so you can use vectors for the individual components. So just look up :biggrin:
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    Math Graphing Problem

    You need to understand how the functions on your calculator work, in order to understand how to do this. You are correct in using the max. and min. functions, but you are working too hard to find the parameters. When you input the right and left bounds using the maximum function, the located...
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    Please Help Grd 11 student

    In this case, because of the function of the parachute, the air resistance would be the equivalent of the Force exerted by the parachute. So you do not need to calculate air resistance, once you find Fp you will already have it.
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    Help for a short question

    I see that now :biggrin: tricky tricky
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    Momentum and circular motion

    What you are describing is a ballistic pendulum. A simple device used to measure the speed of a projectile. v = \frac{m+M}{m}v' = \frac{m+M}{m}\sqrt{2gh} H will be as Tide mentioned the distance it rises. You can find that by finding the y component of the angle. P.S. I skipped the...
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    Article about long range artillery

    In addition to CollectiveRocker's post, considering that this is k-12 you most likely do not need to include any information on wind resistance and change in gravity. So include in your paper how the projectile motion of the artillery is parabolic. A more broad topic, would be to research...
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    Momentum collision difficulty

    1/2{m_1}{v_1}^2 + 1/2{m_2}{v_2}^2 = 1/2{m_1}{v'_1}^2 +1/2{m_2}{v'_2}^2 Conservation of KE has a coefficient of 1/2. Also just a hint, In an elastic collision the relative speeds of the two objects will be the same before and after the collision. Just opposite directions. :p And mass does...
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    Help for a short question

    Umm.. I do not recollect ever mentioning Galileo in that response. Actually I am sure I did not.... because that does not even have relation to him.
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    Find the coefficient of kinetic friction problem

    Thank you for pointing that out. I believe I calculated it neglecting the magnitude of the angle. So I just said that the forces perpendicular to the displacement cancel. But the equation is still right!
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    Find the coefficient of kinetic friction problem

    You need to remember that for the net work on the bag, you must include the other factors. The crate's weight, friction, normal force, and the force applied by the women. Because the normal force and weight are equal forces, and act in opposite directions they will cancel out. So you will...
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    Help for a short question

    Because the man is holding the book while he is walking, you can consider it part of the system. Thus no work is done individually on the book. And if the man is moving with a constant velocity then no work is done at all. The only forces acting on the book are the gravitational and the normal...