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## Homework Statement

[tex]\sum_{n=2}^{\infty}sin(\frac{\pi*n}{2})/{2}[/tex]

I dont have a solution, and wondered if the execution is correct.

## The Attempt at a Solution

I thought that one can use comparison test where; [tex]\sum b_n[/tex]= [tex]\frac{1}{n^{1/2}}[/tex].

Since p<1 ---> divergent. But many of the students says it converges. Some suggestions?

We know that the series is alternating, and if I use its test I get that it converges. Reckon that perhaps the fault lies there?