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  1. 6

    Hall Effect for Dummies

    The Lorentz force causes the electrons to clutter, which creates a voltage?
  2. 6

    Hall Effect for Dummies

    Can someone explain the Hall Effect? If electrons are moving inside a magnetic field that is perpendicular to the wire, then perpendicular to both the wire and the magnetic field will be a resultant voltage? Why does this voltage arise?
  3. 6

    Hall Effect

    Is the Hall Effect quantum physics?
  4. 6

    Planck and light particles

    Did Planck think that light was a particle or a wave?
  5. 6

    Energy of hydrogen atoms

    The combined energy of the two hydrogen atoms when they come together to form H2.
  6. 6

    Energy of hydrogen atoms

    Why is it that when two hydrogen atoms combine together, their combined energy is less than the energy of one hydrogen atom by itself? Why wouldn't the combined energy be twice as much?
  7. 6

    Digital Electronics: State machine

    When both J and K are 0, then there is no change in outputs. When they are both 1, then the outputs are toggled. A B Y Next X Next Y 0 0 0 I still get stuck at this part. I can tell that next Y is going to be 0, but I can't say what next X is, because the table doesn't tell me what X...
  8. 6

    Digital Electronics: State machine

    A B Y Next X Next Y 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 I'm a little bit confused as to what to do after this. I see the equation AB'Y + A'BY' going into J and K. So that means that J and K will always be the same. Is that right?
  9. 6

    Digital Electronics: State machine

    Homework Statement (a) How many states does this system have? (b) How many rows will there be in a state transition table? (c) Provide the state transition table. (d) Draw a state diagram of the system. (e) Describe what the circuit does in words. Homework Equations The Attempt at a...
  10. 6

    Effective mass of a charge carrier

    What is the effective mass of a charge carrier, numerically? Is it equivalent to the mass of an electron? Is it the same for negative charge carriers as it is for positive charge carriers?
  11. 6

    How to measure voltage rise delay and fall delay?

    In Cadence we built a CMOS inverter. I made a transient response graph showing the input and output voltage waveforms. We're supposed to measure rise delay and fall delay of the output voltage. How do I do this? I heard from someone else that it's where the graphs cross 1.5V, but I'm still...
  12. 6

    Solving Schrodinger equation in two dimensions

    How about this. Since the probability of finding the particle outside the box with dimensions Lx and Ly is 0, then the wavefunction must go to 0 outside of these limits.
  13. 6

    Solving Schrodinger equation in two dimensions

    V is not in the denominator so it will not make anything go to 0. It will just create an infinitely large number. A wavefunction is continuous and therefore differentiable everywhere. So at the boundaries it will also be differentiable.
  14. 6

    Solving Schrodinger equation in two dimensions

    What is the equation for the wave function?
  15. 6

    Solving Schrodinger equation in two dimensions

    I'm not even sure what the boundaries are.
  16. 6

    Solving Schrodinger equation in two dimensions

    Are you sure there isn't a typo? The first equation says Y(+Lx/2,y) and the second says dY(+Lx/2,y)/dx
  17. 6

    Solving Schrodinger equation in two dimensions

    I know that psi is not Y, I just don't know how to type it in here so I just use Y instead.
  18. 6

    Solving Schrodinger equation in two dimensions

    I thought that in the equation there are two Ys. One is Y(x) and the other is Y(y). So Y is actually Y(x,y)? I don't know what to say about those equations. Any hints?
  19. 6

    Solving Schrodinger equation in two dimensions

    Can I just skip over to X''(x)=0, and then integrate twice to solve for X? Then that becomes X'(x) = X + C1 X(x) = XC2 + C1
  20. 6

    Solving Schrodinger equation in two dimensions

    So if C = 0, then r1 = r2 = 0 so the equation is X = Ae^(sqrt(C)x)+Bxe^(sqrt(C)x) X = Ae^0 + B(0)e^0 X = Ae^0 X = A Is that right?
  21. 6

    Solving Schrodinger equation in two dimensions

    How is it that X = Ae^(ikx) + Be^(-ikx) is the same as X(x)=Asin(kx)+BCos(kx)? Is there a name for that rule? If C = 0, I don't see why that doesn't turn X = Ae^(sqrt(C)x) + Be^(-sqrt(C)x) into X = Ae^0 + Be^0 Just plug in right?
  22. 6

    Solving Schrodinger equation in two dimensions

    X = Ae^(sqrt(C)x) + Be^(-sqrt(C)x) if C = k^2 then the equation is X = Ae^(kx) + Be^(-kx) if C = -k^2 then it is X = Ae^(ikx) + Be^(-ikx) (not sure about this one) if C = 0 then it is X = Ae^0 + Be^0 = A + B
  23. 6

    Solving Schrodinger equation in two dimensions

    X'' - CX = 0 r^2 - C = 0 r^2 = C r1 = C r2 = -C X = Ae^(Cx) + Be^(-Cx) Is that much correct? Now do I plugin initial and final conditions to solve for the constants, or do I first have to find the particular solution?
  24. 6

    Solving Schrodinger equation in two dimensions

    It's been a while so I'm not too confident with solving the ODE. I think that I have to create a characteristic equation, and I'll find solutions s1 and s2, and plug that in to an equation like Ae^(s1)+Be^(s2), then plugin initial values to find A and B? Is it something like that?
  25. 6

    Solving Schrodinger equation in two dimensions

    Yes, functions of a variable can be equal to a constant, I just suspected that wasn't the case here. If X''(x)/X(x) = C, then X(x)''/X(x) + Y(y)''/Y(y) = -2m/h^2*E C + Y(y)''/Y(y) = -2m/h^2*E Y(y)''/Y(y) = -2m/h^2*E - C If that is correct, then I think that the integral should be taken...
  26. 6

    Solving Schrodinger equation in two dimensions

    I just remembered that they can be constants since they are second derivatives. A variable can disappear when taking derivatives.
  27. 6

    Solving Schrodinger equation in two dimensions

    If both functions are constant, then adding them together would result in a constant, but I don't see how they can be constants since they have variables in them.
  28. 6

    Solving Schrodinger equation in two dimensions

    Yes, x and y are independent. A function of x and a function of y added together will result in a constant when the variables cancel each other out or become 0.
  29. 6

    Solving Schrodinger equation in two dimensions

    X''(x)/X(x) is a function of x and Y''(y)/Y(y) is a function of y. Are you asking when X(x)''/X(x) + Y(y)''/Y(y) + 2m/h^2*E = 0 will be equal to 2m/h^2*E = 0 ? If that's the case, then it will happen either when both X(x)''/X(x) and Y(y)''/Y(y) are equal to 0, or when X(x)''/X(x) =...
  30. 6

    Solving Schrodinger equation in two dimensions

    X(x)''/X(x) + Y(y)''/Y(y) + 2m/h^2*E = 0
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