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H
Logarithm problem
ok i went ahead & solve the equation to get x=0.522....but when i substitute x=0.522 into the initial equation i did not get 2...what hv i done wrong?
helmi
Post #4
Oct 6, 2006
Forum:
Precalculus Mathematics Homework Help
H
Logarithm problem
ok ive done the 1st step by changing log2 2x to (log3 2x)/(log3 2) (log3 2x)/(log3 2) - log3 (3x-1) = 2 1.585(log3 2x) -log3 (3x-1) = 2 log3 (2x)^1.585 - log3 (3x-1) = 2 log3 ( (2x^1.585)/(3x-1) ) = 2 , is this correct? then what?
helmi
Post #3
Oct 6, 2006
Forum:
Precalculus Mathematics Homework Help
H
Logarithm problem
log2 2x -log3 (3x-1) = 2, solve for x.... you guys dont hv 2 solve the question for me, just guide me to the answer:smile:
helmi
Thread
Oct 5, 2006
Replies: 3
Forum:
Precalculus Mathematics Homework Help
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