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  1. S

    Theory of relativity and time

    and the most accurate way of timing the two events lets say a person observing and the person in the event (like in the rocket) is the cesium clock.
  2. S

    Circular aperture

    ok xanthym, i get the whole concept now... thanks for the effort.. i now understand.. =)
  3. S

    Circular aperture

    u mean to say it is in radians? how can i convert it to degrees? is it divide by 180 or times 180?
  4. S

    Circular aperture

    ok, i seem to understand it, but why is my answer incorrect to the book? my answer is 3.344676923x10^-5 whereas in the book, it is 0.00192 degrees?
  5. S

    Circular aperture

    ok xanthym, i get it now... all the whole thing.... i can grasp what u mean, but where did the 2nd formula came from in 3rd messsage?? is it a relationship in what?
  6. S

    Circular aperture

    space tiger, what i mean is how can i derive another formula, coz tetha=1.22(lambda)/D this is the only formula i know for now... since there is speed, how can i apply it to the formula... can u derive me some formula and can u explain it step by step...
  7. S

    Help Single slit diffraction

    ok xanthym.. thanks for the big help... now i understand now
  8. S

    Help Single slit diffraction

    xanthym, i know what u mean... but im not familiar with the formula u said... so u mean.. 1.22 is the m?
  9. S

    Circular aperture

    Here is the problem... Calculate the resolving power of a microscope with a 1.30cm aperture using 540nm light. The index of refraction of the lens slows the light inside the glass to 1.98x10^8m/s. i just know the formula tetha=1.22(lambda)/D, but i dont know how to derive the formula since i...
  10. S

    Help Single slit diffraction

    where did u get the formula for this?? i just know the formula... tetha = 1.22(lambda)/D... can u tell me how u derived from that formula??
  11. S

    Help Single slit diffraction

    how about for this problem... Commercial satellites are able to resolve objects separated by only 1.0m. If those satellites orbit the earth at an altitude of 650km, determine the sixe of the satellites' circular imaging aperture. Use 455nm light for the light in the lenses of the satellites...
  12. S

    Help Single slit diffraction

    oh now i see.. thanks again man..
  13. S

    Help Single slit diffraction

    but why do u have to do that .. i mean multiply it to 2??
  14. S

    Help Single slit diffraction

    yeah i got teh right answer... thanks so much man..
  15. S

    Help Single slit diffraction

    i just have to multiply my answers to 2 or ...??
  16. S

    Help Single slit diffraction

    yes, thats what i did.. but why is my answer incorrect to the answer in the book... it should be 7.3x10^-3m for the red light..
  17. S

    Help Single slit diffraction

    and the value for W is 6.9x10^-5?
  18. S

    Help Single slit diffraction

    im so confused... wat is the unknown here?? is it L or Y?
  19. S

    Help Single slit diffraction

    anyone HELP me please..
  20. S

    Help to writr a math poem,

    ... heya toxic, can u help me with my HW?
  21. S

    Help Single slit diffraction

    Help!! Single slit diffraction heya all... this is the problem.. Predict whether violet light(lambda=404nm) or red light (lambda=702nm) will have a wider central maximum when used to generate a single-slit diffraction pattern. Calculate the difference if the light is incident on a 6.9x10^-5...
  22. S

    Magnetic fields and charges

    whozum.. ok i get the process and solution you gave to me, but how can i apply the two charges... should i find the F first for the two charges and what should i do next??
  23. S

    Magnetic fields and charges

    whozum, i still dont get the concept behind this.. how can i apply if there is given charges??
  24. S

    Magnetic fields and charges

    check this if this is right??? F/2N = 1.2x10^-11/4r^2 the new force i get is 6x10^-12N.. it is wrong, how can i get 0.17N? it's kinda hard to think about it...
  25. S

    Magnetic fields and charges

    so the equation is like this... F is directly proportional to ((6.0x10^-6C)\(2.0x10^-6C)/(2r)^2)/(q1*q2/r^2)???
  26. S

    Magnetic fields and charges

    magnetic fields how about this problem... Two identical object have charges of +6.0µC and -2.0µC, respectively. When placed a distance d apart, their force of attraction is 2.0N. If the objects are touched together, then moved to d distance of separtion of 2d, what will be the new force...
  27. S

    Satellites again

    thanks so much for the help, xanthym!! hope u can help me again... heheh =)
  28. S

    Satellites again

    ohh yeahhhh... i forgot
  29. S

    Satellites again

    pioneer u know that the Pioneer has no given mass?? so what will i put to the m in 1/2 mv^2 nad GmM(1/r - 1/r)?
  30. S

    Satellites again

    xanthym, i dont know the {Earth's distance from sun "Dearth"}. can u give me the value for that?
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