yes, I know it is really not circular but It will be assumed in this probem.
I used f=ma to come up with vi=sqrt(GM/ri) & vf=sqrt(GM/2rf)and plugged in those as V on both sides (with the corresponding r)
I got 2 ri = rf
1. Homework Statement
(Assuming all circular orbits)
Say there is a star with mass M and a planet orbiting that star with a mass m.
The star M then suddenly loses half of its mass. (So now it is M/2)
What is the new radius of orbit of the planet around the star? Warning: Velocity will not be...
Ok, I came up with this: but I don't know the initial/final velocities of the moon. I could use 2 pi r / T if I was given T but I am not
r x p = rp (since right angle)
Iω + r x p = Iω + r x p
IEarth ωearth initial + dinitial vinitial mmoon = IEarth ωearth final + dinitial vfinal mmoon
Oh I understand how the earth slows down now. But why does this affect the moon's orbit? Because the force of gravity doesn't change because the earth does not become more massive or something
1. Homework Statement
we know the mass of the moon, Mm, and the earths, Me, and also the initial distance between their centers as the moon orbits the earth, Rem.
Now if the earth’s angular velocity about its own axis is slowing down from a initial given angular velocity, ωi to a final angular...
Hmm so I guess if we think of them as 3 separate PEs then 2 of them are decreasing when the 3rd is increasing. so that would change pe. i see that now. But still, the whole system looks static, like it is not moving or changing. Is there some kind of force that would push the middle one down...
1. Homework Statement
Find the potential energy function for the three mass, earth, and pulley system as shown. The potential energy will be as a function of the vertical position downward as shown in the diagram. Also, find the equilibrium position of this system. The two outside masses are...
yeah I did that in the equation above. for the y, -mgcosΘ+Fn are the 2 forces acting on the block. (slanted frame). amgy just means the acceleration of the mass relative to the ground in the y direction
Yes,
Amg is acceleration of m relative to g
Aeg is acceleration of elevator relative to ground.
Since I cannot use fictitious forces I need to use relative accelerations.
Amg=Ame+Aeg just shows that the a of the mass relative to the ground is the sum of the 2 relative accelerations vectors
1. Homework Statement
MECHANICS:
Given Theta, L, M, and acceleration of elevator relative to ground. Find the time it takes for the block to reach the end of the incline.
Here is a diagram: http://k-elahian.com/tmp/nip.PNG [Broken]
2. Homework Equations
f=ma
kinematics
relative...