So I plotted it out, and by inspection I concluded that the limits are:
0 \le r \le 3
0 \le z \le 3
0 \le \theta \le 2 \pi
However, I can't get past the integral:
\iiint_V r \sqrt{r^2 + z^2} \,dr\,dz\,d \theta
gives
\iint_V \frac{1}{3} (r^2 + z^2)^(3/2) \,dz\,d \theta...
Apologies but I still can't get it to work out. My limits are:
3 \le r \le z
3 \le z \le r
0 \le \theta \le 2 \pi
I'm fairly sure this is wrong, but can't figure out the correct ones
1. Homework Statement
The problem states: Use cylindrical coordinates to evaluate
\iiint_V \sqrt{x^2 +y^2 +z^2} \,dx\,dy\,dz
where V is the region bounded by the plane z = 3 and the cone z = \sqrt{x^2 + y^2}
2. Homework Equations
x = r cos( \theta )
y = r sin( \theta )...
Stuck on this problem also!!
I get to a stage where I get a massive cubic equation...I'm assuming I've gone wrong somewhere...
Any help? Or any online resources where the problem is worked through...?
I was thinking along the lines of this, but I noticed that on each circuit breaker it says 20A and there are around 30 of them. Does that make a difference?
Haha yeah it is the electrical panel, but its actually made of metal.
I still don't understand why that fuse blew instead of one of the circuit breakers switching?
Thanks dlgoff for the prompt reply. I'm not too sure about this. Would the circuit breakers not already be hot considering I had many devices on at the time?
Thanks
Ed
Hi all!
I have an issue with the circuit breaker in my house and was wondering would anyone be able to shed some light on whats going on.
So last night, I plugged in the hoover and all the electrical devices in my house switched off. I wasn't surprised as I had many devices on at the time so I...
Hi all,
I am trying to prompt the user to enter a mathematical function in matlab.
Any suggestions on how to do this?
I have looked at the inline functions but I am not sure how to code it.
Any help is greatly appreciated.
Ed
Hi Sarah,
Ok so I think you should revise the principle of conservation of charge.
In this case, a useful approach would be to remember that the charge on the left hand side of an equation is equal to the charge on the right hand side of the equation.
For example, analyse question a) p...
Everywhere and nowhere!
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Well there are only a few properties that differ greatly between gold and silver. For example atomic weight/number and therefore its specific gravity, boiling point...
I'm guessing the solution will be of some relevance to Archimedes... So I feel that you're on the right track by measuring the...
1. Homework Statement
Is it possible for a gamma ray to interact with a free electron by mean of the photoelectric effect?
2. Homework Equations
3. The Attempt at a Solution
I'm not really sure. I think the answer is no simply because of the mechanics of the photoelectric...
1. Homework Statement
\int \frac{sin(\sqrt{x})}{\sqrt{x}} dx
2. Homework Equations
3. The Attempt at a Solution
I'm not too sure how to approach this. The only thing that rings a bell at this moment is
\lim_{x\to\0} \frac{sinx}{x} = 1
and I don't feel that it is of any...
1. Homework Statement
Show that if motion could occur at arbitrary speed, then time travel would be possible.
2. Homework Equations
3. The Attempt at a Solution
I'm not sure where to start of. I'm guessing that it has something to do with the light-cone and space-like vectors...
1. Homework Statement
A point charge q is placed at one corner of a cube of edge a. What is the flux through each of the cube faces?
2. Homework Equations
3. The Attempt at a Solution
I drew a diagram of the situation. I'm pretty sure that I should use Gauss' Law and some...
1. Homework Statement
Let x = (x,y,z) .
Recall that the vector x is determined by its direction and length
r = |x| = \sqrt{x^2 + y^2 + z^2}
and assume we are given a function f which depends only on the length of x
f = f(r)
Show that
\Delta f = f'' + \frac{2}{r} f'...
Ok cool thanks so it is
R^2 -12R +20 = 0
R=2 and R=10
Therefore the equations of the circles are
(x- R)^2+ (y+ R)^2= R^2
(x- 2)^2+ (y+ 2)^2= R^2
and
(x- 10)^2+ (y+ 10)^2= R^2
Just out of curiosity what was wrong with my original attempt?