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    What's your favorite movie?

    The Talented Mr Ripley, Get Shorty, The Mission, 12 Angry Men, Howard's End.
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    Memorization for History Exam

    Or you can use a strategy that has been put forward in a book here recently in Norway. A guy who's world top at memorizing cards use two techniques: travelroute and images. You use familiar places, like your home, and walk through each room. You'll recognize these rooms very well because it's...
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    General Integral rules

    yes, i am. Yeah, I figured. Like this right?: \int 5 x e^{x^2}dx = 5/2§2xe^(x^2) = 5/2§ (and as in opposite of the above e^(x^2)*2x) = (e^(x^2)) , which gives simply 5/2(e^(x^2))+C.
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    General Integral rules

    so.. : testing.. \int 5x e^{x^2}dx = 5/2 \int 2x e^{x^2}dx = 5/2\times2\times \frac{1}{1+1}x^1+1
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    General Integral rules

    no, it's rule 2? e^(x^2)= 1/x^2*e^(x^2), it would make the x^2 dissapear anyway.. and would make sense at the least.
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    General Integral rules

    (e^u)`*u` I'm making a fault here? no chain rule in integral? e^(x^2)=e^(x^2)? , but why isn't chain rule being used? (like in §e^(3x-2)dx=(1/3)e^(3x-2)+C.) it looks like it should, heh. And how do the x^2 dissapear..
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    General Integral rules

    Where do I find LaTeX? Yeah, I meant chain rule. in is natural logarithm, e^inp=p. My try went: §5x*e^(x^2)dx= 5/2§2x*e^(x^2)dx (cause here is where you 'use it', right? = 5/2*2*(1/(1+1))x^(1+1)*(e^u)`*u` (chain rule) = 5/2*x^2*e^(x^2)*(1/(2+1))x^(2+1) = 5/2x^2*e^(x^2)*(1/3)x^3+C.
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    General Integral rules

    oh no, sorry the answer is: (5/2)*e^(x^2)+C... (at work, brb)
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    General Integral rules

    Homework Statement Solve (e^(x^2))` , use this result to solve §5x*e^(x^2)dx Homework Equations * is multiply ` is derive 1.§e^xdx=e^x+C 2.§e^kxdx=1/k*e^kx+C 3.§a^xdx=1/ina*a^x+C (a is a number) 4.§k*f(x)dx=k*§f(x)dx The Attempt at a Solution (I'm alittle confused as to...
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    Probability with independent outcomes

    uh, are you joking with me, or am I writing down the question wrong(cause I know I have a bad habit of not reading the question at probability well enough)? Cause that was the way I was thinking as you above.
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    Probability with independent outcomes

    Yeah, b| the probability of that the eldest is a brother, and the two youngest girls. That is also just one outcomes yes? So that should give 1/8. But the answer writes as 0.121, which is not 1/8. ???
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    Probability with independent outcomes

    Yeah, I guessed so too, but then I've thought so before too and being wrong, so.. *g* Hm, I'll ask about b| soon.
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    Probability with independent outcomes

    Jeeserssweesers(for a lack of a better word), probability is confusing. Homework Statement A family has three children, no twins or.. that same just with three. a| What is the chance that all the children are girls. Homework Equations The chapter here shows the equtations...
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    What's the point of life

    Another guy that wants to shout out his oppinion without reading all that's before him. For me it is different in that I find much meaning, but I also feel small. I'm supporised when someone says they can't find meaning in anything for to me there is so much. Maybe if you can't find a meaning...
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    Why do men weep

    I cried to Jerry Springer when I was 16 or something when I was at my friends place, I couldn't watch it and had to leave, heh.
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    Independent Probability

    Or "Red at least once means 3 out of 4 outcomes. the 3 outcomes is defined by 'first spin is red', "third spin is not red", "fourth spin is red", and last as 'can be anything'" (Taking out my favorable/can-be-anything. uh, something like that? Closer? Grr, I don't like getting math not to...
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    Independent Probability

    No, I was just kidding around when I said just the variables. I always hope I'm good at humour but I'm not. My thought went as above(in case you haven't seen it): we have two spins, divided by a +. First shows the probability-of-one red and probability-of-can-be-everything(uh), the...
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    Independent Probability

    Hm, because ...? I have to go to work. I'll take little look into it before I reply again! This is fun and helpful.
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    Independent Probability

    Good question. Because we have all the variables? Not enough?! Because.............. we have two spins, divided by a +. First shows the probability-of-one red and probability-of-can-be-everything(uh), the second of probability-of-one-red and probability-of-one-red. We have all the...
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    Independent Probability

    I think I liked can-be-anything definition better. hm, the 7/8 is a bit confusing to me. I'm abit visual and thinking 7/8 which is 'such a big number' is nothing falls unatural, but this is probably(whaha what a pun) quite normal.
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    Independent Probability

    can be anything.... wow. (Edit: Yeah well that is I suppose my "those that might happen") (7/8)(1/8) is first-spin-no-red x second-spin-one-red
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    Independent Probability

    Riight, I'll get some balls. hehehe. No I mean.. directly translated it's favorable/those that might happen. They are strange words to me. Uh. (Edit: Or it's like I see the math and don't see the math. Strange)
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    Independent Probability

    heh, pulling out balls from a bag was my previous test. I'm having these sentences in my mind, but they fall out again fast. I must specify...... one red(R) x all(=NN)or:(8/8) , (I have these RN NN things alot in my mind here, lol) ? hm...
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    Independent Probability

    I'm not sure how you say in english, but here(norway) it's G/M(gunstige(all the probable(or wanted)/mulige(all the possible outcomes), and use it alot(?) through probability.
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    Independent Probability

    AND you get the possble into it also. Are we sure this is probability and not magic? *laughs* But shoudn't I as I think, putting it into that / ? So I get the 8/8 at the bottom as the possible And also I'm maybe a little confused as to how you would get to the answer from the other way...
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    Independent Probability

    Well approximately it's right because you have all the 3 spins and the probable and possible. But.. ah yes, it doesn't matter of course that you muliply the 8/8 into it because anything muliplied by 1 doesn't change.
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    Independent Probability

    But that woulnd't make sense above cause then 8/8 is multiplied into both factors..
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    Independent Probability

    (1/8)(8/8) + (7/8)(1/8) Why is the 1(8/8) at just one side?.. Because it doesn't have to be more of it? I'm a little confused at it's presentation. How do I transform it from that, to ((1/8) + (7/8)(1/8)(probable)) / (8/8/(possible))
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    Independent Probability

    But I'm thinking as above: " all is the possible and the rest is the probable(3). That would make perfect sense(?) uhm. It's as if you make a division into a sentence. O_o you'd have to multiply the 'no red x one red' with 'all' to make it a whole division "
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