# Search results

1. ### Static Equilbrium

Thanks for all your help, but I couldn't figure the last part out, and the assignment was due today. I REALLY APPRECIATE ALL YOU HAVE DONE. Thank you.
2. ### Static Equilbrium

Homework Statement The system at the right is in static equilbrium, and the string in the middle is exactly horizontal. Find a) tension T(1) b) tension T(2) c) tension T(3) d) angle thetas **I don't know if anyone can help me with this because I cannot upload the picture. Any help...
3. ### Static Equilbrium

Ok here we go again: I really appreciate your help. F(fr)=F(w) F(fr)=mu F(n) =.4(117)(9.8) =458.64 N Thus, T(wall)=F(w)(L)(sin 65) =(458.64)(10)(sin65) =4156.69 Now, I am still lost on T(painter). 1. t=rFsintheta: here is the angle between the...
4. ### Static Equilbrium

Here we go: T(wall)=Fw* L *sin theta =267.89*10*sin 65 =2427.90 T(ladder)=-22 (9.8) (10/2) (cos 65) =-455.58 T (painter)= mg (h) =(95)(-9.8)(h) =-931h 0=2427.90-455.58-931h x=2.104 meters Where did I go wrong?
5. ### Static Equilbrium

Ok, here is what I found: T(wall)=2427.90 T(ladder)=-455.58 T(painter)=-931x 0=2427.90-455.58-931x x=2.104 meters up ladder How does it look?
6. ### Static Equilbrium

I used the following formula: sum torque=F(w) * l (sin theta) - mg * L/2 cos theta=0 m=22kg THis is what I got: torque=267.89 * 10 * sin 65 - (22)(9.8) * (10/2) (cos 65) =4674.19 N What am I missing????
7. ### Static Equilbrium

Was my attempt at solving anywhere close to what I am looking for? Thanks.
8. ### Conservation Laws in Rotational Motion Physics

Thank You Again!!!!!!!!!!!!!
9. ### Static Equilbrium

Homework Statement A window cleaner of mass 95 kg places a 22kg ladder against a frictionless wall at a angle 65 degrees with the horizontal. The ladder is 10 m long and rests on a wet cloor with a coefficient of static friction equal to .40. What is the max lenght that the window cleaner...
10. ### Conservation Laws in Rotational Motion Physics

Here is what I did: 2) KE=1/2MV(cm) + 1/2 I(cm)w^2 =1/2(2.5)(2.0) + 1/2(.0196)(204.08) =4.99 J 3) L=Iw =(.0196)(204.08) =3.99 J
11. ### Conservation of Mechanical Energy

Thank You~!!!
12. ### Conservation Laws in Rotational Motion Physics

Ok, I recalculated and found: 1) 2 J 2) 4.99 J 3) 3.99 J
13. ### Conservation of Mechanical Energy

Because they cancel??
14. ### Conservation Laws in Rotational Motion Physics

Did I forget the square on #2? Is that what you are saying? Thanks.
15. ### Conservation of Mechanical Energy

My apologies, they represent the radius. I didn't mean to use different symbols.
16. ### Conservation Laws in Rotational Motion Physics

Homework Statement A uniform solid sphere, with diameter 28 cm and mass 2.5 kg, rolls without slipping on a horizontal surface, at constant speed of 2.0 m/s. 1) What is the rotational kinetic energy? 2) What is its total kinetic energy? 3) What is its angular momentum? Homework...
17. ### Conservation of Mechanical Energy

Homework Statement A massless string is wrapped around a solid cylinder as shown in the diagram. A block of mass 2kg hangs from a string. When released, the block falls a distance of 82 cm in 2.0 seconds. Calculate the mass using the conservation of mechanical energy. Homework...
18. ### Rotational Dynamics of a meter stick

Sorry, I just saw your post. Let me check it again. Thanks.
19. ### Rotational Dynamics of a meter stick

I think I figured it out. I had my I(cm) in the wrong place of the equation. I now found that I=.0762. THanks!!!!
20. ### Rotational Dynamics of a meter stick

I found that I=.0366 kg/m. Now, I used I=I(cm) + m(d^2). .0366=I + (.44)(.3^2) I=-.003 I know I did something wrong. Did I use the wrong distance?
21. ### Rotational Dynamics of a meter stick

My mistake, I misunderstood you. The formula I found for a long uniform rod was I=1/12(M)(L^2). For L, so I consider it as 1 meter? Or do I use .5 m? I am not sure what you mean by parellel axis theorem. Thanks!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
22. ### More Rotational Dynamics

I am confused about the KE(cylinder) in the above equation. Can someone please explain this? Thanks.
23. ### Rotational Dynamics of a meter stick

Relavent formula: I=(sum of t)/angular acceleration
24. ### Rotational Dynamics of a meter stick

Should I assume that 30 cm is the middle of the rod? Thanks.
25. ### Rotational Dynamics of a meter stick

Homework Statement A meter stick of mass .44 kg rotates, in the horizontal plane, about a vertical axis passing thru the 30 cm mark. What is the moment of inertia of the stick? Treat it as a long uniform rod. Homework Equations I=1/2M(R^2) The Attempt at a Solution...