The system at the right is in static equilbrium, and the string in the middle is exactly horizontal. Find a) tension T(1) b) tension T(2) c) tension T(3) d) angle thetas
**I don't know if anyone can help me with this because I cannot upload the picture. Any help...
Ok here we go again:
I really appreciate your help.
Now, I am still lost on T(painter).
1. t=rFsintheta: here is the angle between the...
Here we go:
T(wall)=Fw* L *sin theta
T(ladder)=-22 (9.8) (10/2) (cos 65)
T (painter)= mg (h)
Where did I go wrong?
I used the following formula: sum torque=F(w) * l (sin theta) - mg * L/2 cos theta=0
THis is what I got:
torque=267.89 * 10 * sin 65 - (22)(9.8) * (10/2) (cos 65)
What am I missing????
A window cleaner of mass 95 kg places a 22kg ladder against a frictionless wall at a angle 65 degrees with the horizontal. The ladder is 10 m long and rests on a wet cloor with a coefficient of static friction equal to .40. What is the max lenght that the window cleaner...
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My mistake, I misunderstood you. The formula I found for a long uniform rod was I=1/12(M)(L^2).
For L, so I consider it as 1 meter? Or do I use .5 m?
I am not sure what you mean by parellel axis theorem.
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The Attempt at a Solution...