Hmm okay, so that puts it in the form
∫ x^5 / √[(x-(a/2))² - (a²/4)] dx
One possible substitution seems to be u = x-(a/2) but that puts it in the form
∫(u+(a/2))^5 / [u²-(a/2)²] du = ∫ (u+(a/2))^(9/2)) / [u-(a/2)] du
which doesnt seem alot better than what we started with. A trig...
Is there a simple way to evaluate
S x^5 / [rt(x^2-ax)] dx ?
That is, the indefinite integral of (x^5) / [square root of (x^2-ax)].
The Attempt at a Solution
My idea was to rewrite it as x^(9/2) / [rt(x-a)] and then do the substitution u = rt(x-a).
Then you get