Search results

  1. B

    Factorising a differntiated equation

    but i still do not get the chain rule. my text book says that , by the waY.
  2. B

    Factorising a differntiated equation

    Oh oh, i got the last part , now(had to work it out in a piece of paper first...oops)
  3. B

    Factorising a differntiated equation

    I do not understand why is it so does not the chain rule state that dy/dx=dy/du *du/dx hence, when y= U^n dy/dx= (nu^n-1) * (du/dx) so v = (4x-3)^1/2 then dv/dx=1/2(4x-3)^(1/2 -1 ) *(4) =2(4x-3)^-1/2 (correction to my previous equation with that was...
  4. B

    Factorising a differntiated equation

    Hello there, I'm quite weak in factorising functions,especially those with indices. I would appreciate any link on these kind of factorisation or even some tutoring on it. this is a question I'm stuck in. y=(2x+3)(4x-3)^1/2, show dy/dx can be written in the form kx/(4x-3)^1/2 my...
  5. B

    Division by ZERO

    I too would like some explaination about these statements.:bugeye:
Top