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1. Definite integral

Yes that is how I wrote it. How should I solve the second part? I've been looking everywhere... The only thing I could find was that it's supposed to be the anti derivative.. Well 3x is the antiderivative of 3 isn't it?
2. Definite integral

All right, well this is probably wrong but here is what I got! I took out the 2, which I didn't I could do which is probably what confused me the most.. I'm having trouble with the symbols right now but I essentially put the 2 in front of the integral of the function and substracted the...
3. Definite integral

\int^{6}_{3} f(x)dx = 42 - 12 = 30 Is this correct? If so I don't know how 2f(x)-3 will affect the integral without knowing what the actual function is... I must be missing something
4. Definite integral

That's probably what the question is and I'm assuming it was a typo. I will ask tomorrow for sure but in the mean time how would I solve if the question were indeed what gb7nash thinks? I have looked through all of my notes and can't find anything to get me started...
5. Definite integral

We don't have a text book for this class.
6. Definite integral

Mark44 - I copy and pasted the actual question. However, my prof is chinese so maybe that's why the question seems confusing? I really don't understand what he wants me to find...
7. Definite integral

The function isn't given so I'm not quite sure how to do this. We've only learned how to calculate area beneath the curve with simple geometry and to use the Riemann sum.
8. Definite integral

The thing is, it that last equation is correct. It is =12. Which is why it doesn't make sense to me.
9. Definite integral

We are just starting integrals right now and I'm having trouble with this problem. I know how to solve a definite integral but I don't quite understand what is being asked here? Just wondering if anyone could let me know where I should start? if∫0,3f(x)dx=12, ∫0,6f(x)dx=42,find...
10. Limit problem

Thanks! It should be 6x right? So is 1/6 the correct answer?
11. Limit problem

Here is how I did it in case it might help lim->0 (e^x)' - 1' - x' - (x^2/2)' /x^3' = lim->0 (e^x' - 1' - x')/ 3x^2' = lim->0 (e^x' - 1') / 5x' = lim x->0 (e^x) /5
12. Limit problem

I used L'Hopital's rule three times and ended up with limx->0(e^x)/5 Is this correct? It still gives me 0 on top.
13. Limit problem

If I use l'Hopital's rule won't I end up with 3x^2 at the bottom?
14. Limit problem

Homework Statement Evaluate limx->0 (e^x - 1- x - (x^2/2))/x^3 The Attempt at a Solution I can't remember how to solve this limit. Do I need to evaluate each part seperately? I plugged in the 0 to find that the limit does exist. I just can't seem to figure out what to do next.