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    Prove that the limit of the functions

    Note that e^{ix} is bounded: e^{ix} = \cos(x) + i\sin(x) so, for large, or arbitrary x, e^{ix}, the imaginary part will never be greater than 1, and the real part will never be greater than 1. Thus, if you had: \lim_{x \rightarrow \infty} e^{(i-1)x} the e^{-x} part forces the whole...
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