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1. Pully and Inclined Ramp

Oh, I assumed the two blocks would have the same acceleration as they are all in the same system... Shouldn't acceleration of A be equal to acceleration of B?
2. Pully and Inclined Ramp

Nope.. it shouldn't be.. it should be equal to Ma A, not 0
3. Pully and Inclined Ramp

I'm guessign at that point I could then use: Tnet = [ Tension2 - Tension1]*radius = .5 m r^2 ∝ ? Tension2*cos(22) - Magsin(30) - ( - Tension sin(22) + mgcos(30) )μ = 0 Put this equation in terms of Tension2 solve the hanging block equation for t1 Mb a = T1 - Mb g Tension1= Mb a + Mb g then...
4. Pully and Inclined Ramp

Okay gotcha.. so I guess I can just account for the Ay as 0, meaning my normal force equation would be Normal Force = - Tension sin(22) + mgcos(30) as the 0 would cancel out the mass
5. Pully and Inclined Ramp

oh.. I mean it would be 0, if the crate is remaining on the horizontal floor
6. Pully and Inclined Ramp

I suppose I could just say Asin(22) = Ay... I'm not sure at this point.. this problem has been so drawn out to the point wher ethis isn't helping much anymore..
7. Pully and Inclined Ramp

The y component would be sin() of it... the only thing i am confused about now Now I have ay and ax though? Look I really appreciate your help but going through this step by step has become pretty tedious, what do you think the equation should look like?
8. Two Blocks and a Pulley Friction Problem

Great. Thanks
9. Two Blocks and a Pulley Friction Problem

Homework Statement System comprised blocks, a light frictionless pulley and connecting ropes (see diagram). The 9.0kg block is on a perfectly smooth horizontal table. The surfaces of the 12kg block are rough, with μk = .2 between the two blocks. If the 5.0 kg block accelerates downward when it...
10. Pully and Inclined Ramp

The block is going to accelerate up the ramp... I guess to calculate Ay at this point I would use something like this: Tnet = [ Tension2 - Tension1]*radius = .5 m r^2 ∝ ?
11. Pully and Inclined Ramp

This would be my equation for may, may * acceleration = Normal Force + Tension sin(22) - mgcos(30) I guess I could only solve for the normal force within the whole system of equations, or I could put this in terms of the normal force and solve for this as Normal force in the other equation? If...
12. Pully and Inclined Ramp

Okay, so here is what I think the force diagram is for the block, ignore the other stuff though. So my equation for part 1 is Tension*cos(22) - Ma g sin(30) - ( Ma g cos(30) - Tension*sin(22) )μ = 0 sometimes I think about it such as the equation is parallel and perpendicular. Would this be...
13. Pully and Inclined Ramp

Could I instead use my original equation I used to solve for mass b instead? very lost..
14. Pully and Inclined Ramp

Otherwise.. gonna need some help here.. really not sure what the Y component could be
15. Pully and Inclined Ramp

This was my Y component: 100gcos(30) - (Tension2*sin(22 What should the Y component be then? a little lost.. the axis are tilted.. should it be 100gsin(30) - Tension2*cos(22)
16. Pully and Inclined Ramp

Oh, okay.. i see what your saying.. wouldnt it be something like: 100gcos(30) - (Tension2*sin(22) + 100gcos (30) The tension and normal force acting in one direction, with the force of direction in the other? other wise I am a bit lost here haha Thanks
17. Pully and Inclined Ramp

Hmm, not quite sure what that means, would it be: (100gcos(30) - Tension2*sin(22))/Ma= A
18. Pully and Inclined Ramp

Sorry, Not sure what I ment by that. I put 100gcos(30) - Tension2*sin(22) - Ma A in because I figured that when I calculated the normal force I would need to account of Acceleration as well since it is now moving.. now that I say that it doesn't make a ton of sense to me.. should I have just...
19. Pully and Inclined Ramp

Woops, Thanks for the fast reply. Yeah, that's what I was implying. Looking at the diagram, I was trying to account for the Y side.. and figured that the Y would be changing as well as it is not at rest.. I edited the original post, I stupidly forgot the G. Tension2*cos(22) - Magsin(30) - (...
20. Pully and Inclined Ramp

Homework Statement 100 kg box is held in place on a ramp that rises at 30° above the horizontal. There is a massless rope joint to the box that makes a 22° angle above the surface of the ramp. Coefficients of friction between the box and the surface of the ramp are μk = 0.40 and μs = .60. The...