For part i:
Because this is a finite field, you must show that the polynomial g(X) has no roots in k. Because k is a finite field of 2 elements, you can just try plugging in 0 and 1 because k = {0,1}.
So g(X) is irreducible if and only if 0^2-T is not equal to zero and 1^2-T is not equal...
its very rare around here that i get to help out, so here i go:
http://img144.imageshack.us/img144/830/39461219yw3.png [Broken]
as for the law of sines bit, your formula in there is 100% right, but for the real answer you wanna use the new number you get from plugging in whatever i just gave...
So I was watching some of those physics videos posted in schoolwork board, and although he probably didn't make an error here, I don't think I understand it.
Here's the pictues. I'll elaborate after it so you guys know what I'm talking about...
So anything at all can do work? And in this case, the friction does the work because it forces an object to slow over a certain distance, meanwhile the object just relaxes while the friction does all of the work for it?
I'm not insulted, it's alright.
I took physics in high school, and now I'm trying to learn it with calculus, now that I've completed the class. Somehow I got the impression that plug-and-chug is not how you're supposed to do this stuff when calculus is brought into the equation. Maybe I'm...
Since I'm trying to figure this out, allow me to type what I'm thinking here... hopefully you guys could point out where I'm going wrong:
So since friction has absorbed the energy that was being used to move the block, my goal is to figure out the distance covered by whatever work the friction...
Homework Statement
A 30.0 kg box sliding at 5.00 m/s on a rough surface is brought to rest by 20.0 N of friction. What distance does the box slide?
Homework Equations
KE = 1/2*m*(v^2-v^2)
The Attempt at a Solution
I know that the change in velocity is 5.00 m/s since it is going to...
edited out my answer because i wasn't aware of this rule. way to botch the first post in the forum, eh?
well, to be more helpful without giving an answer:
when you're looking at a graph, it really is rather simple... that purple one sure looks pretty basic, don't ya think? pay attention to...