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  1. AN630078

    Graphs of s, v and a for a mass with a piece of paper attached

    And would the energy-time graph for a damped oscillator be as shown in the attachment ?
  2. AN630078

    Graphs of s, v and a for a mass with a piece of paper attached

    Thank you for your reply. I have attached what I think the displacement tie graph for a draped oscillator would look like. However, I am uncertain how to find the v-t and a-t graphs from this? Would this be correct anyhow for the s-t graph?
  3. AN630078

    Graphs of s, v and a for a mass with a piece of paper attached

    I have no idea, I really am very confused. The question just states " Sketch the following graphs to show how a mass with a piece of paper attached to it varies with time, over a time period of 2T"
  4. AN630078

    Graphs of s, v and a for a mass with a piece of paper attached

    I understand that velocity is defined as the rate of change of position or the rate of displacement; and that acceleration is defined as the rate of change of velocity (it is the derivative of velocity). Morever, I believe I know that for SHM these graphs vary sinusoidally (I have attached a...
  5. AN630078

    Thermodynamics: Internal Energy, Heat and Work Problem

    Well, internal energy is the sum of the kinetic and potential energies of all the molecules within a given mass of a substance; this energy is associated with the random, disordered motion of the molecules. An example of internal energy is compressed gases; since gases occupy the total volume...
  6. AN630078

    Can heat flow into a body without increasing the mean kinetic energy?

    Yes, heat can flow into a body without increasing the mean kinetic energy of its molecules. Transferring heat energy to an object will raise its internal energy, this will not necessarily cause an increase in temperture. Specific latent heat is the energy required to change the state of one...
  7. AN630078

    Why do we not need to convert from degrees Celsius to Kelvin?

    Thank you very much for your informative response and explanation. I see, so it is acceptable to use either unit because the intervals of the scales are equal. 👍
  8. AN630078

    Why do we not need to convert from degrees Celsius to Kelvin?

    I understand that the Kelvin scale begins at absolute zero and that the Kelvin scale may even be referred to as the absolute scale. As the units begin from a definite zero and increase with equal amounts of energy being added to the particles of the substance being measured (at equal intervals...
  9. AN630078

    Alpha, Beta and Gamma Energies

    Well, gamma photons are pure energy, so surely a gamma photon would have the most energy since gamma-ray photons generally have energies greater than 100 keV. An alpha particle has the highest ionising power of the three on account of its mass, it roughly has a kinetic energy of 5 MeV, whereas...
  10. AN630078

    Background radiation sources question

    Thank you for your reply. This is just a a standard A-Level question I was revising, focusing on the topic on nuclear radiation.
  11. AN630078

    Background radiation sources question

    Several sources of background radiation include; Radon gas from soil, rocks and building minerals; since radon is produced by the decay of uranium ore present in certain rocks e.g. granite. On Earth, approximately 42-51% of background radiation is the result of naturally radioactive gases like...
  12. AN630078

    Transformer; make primary voltage x10 of the secondary voltage

    Thank you for your reply. Haha, no presently it is a hypothetical curiosity. Although, perhaps it is an aspiration I will indulge when I feel I have a better theoretical understanding of their functioning. 👍Indeed I will heed your message of caution at any rate.
  13. AN630078

    Transformer; make primary voltage x10 of the secondary voltage

    Thank you for your reply. Oh right, so if the turns ratio is 1:10 not 10:1 would that imply that in order to produce an output voltage ten times the input voltage one would have 10 times turns on the secondary coil than the primary coil?
  14. AN630078

    Transformer; make primary voltage x10 of the secondary voltage

    I understand that transformers function using electromagnetic induction and Faraday's Law. This implies; Vs=-Ns (dΦ)/(dt) Meaning the secondary voltage is proportional to the number of turns on the secondary coil. Vs∝Ns Using the relationship; Vp/Vs=Np/Ns If we want Vs=10Vp that would imply...
  15. AN630078

    Root-mean squared values and a.c. emf

    Thank you for your reply. I am sorry I had misunderstood. So the average power supplied would be 26.45 W? Are parts 1 and 2 correct I forgot to ask 😁
  16. AN630078

    Root-mean squared values and a.c. emf

    Thank you very much for reply. Oh I am so sorry I had not realised that one would integrate to find the average power. So would T=1/f T=1/50=0.02 s ##\int V^2.dt=V^3/3## So does that mean P=1/0.02 * V^3/3= 50*V^3/3=50V^3/3 Substitute V rms = 230 V P=50*230^3/3 P=881666.6667 ~ 882,000 W This...
  17. AN630078

    Root-mean squared values and a.c. emf

    1. We are given the root-mean squared value for the voltage at 230V. Therefore by rearranging the equation Vrms=V0/√2 one can find the value of the peak voltage; ie. V0= Vrms *√2 V0=230*√2 V0=325.269... ~ 325 V (which is the peak voltage of mains electricity in the UK). To find ω use the formula...
  18. AN630078

    Graphical Transformation of y=ln (x)

    a. I believe that y=ln(2x) is a horizontal stretch of y=ln(x) of scale factor 1/2. In the transformation y=ln(2x), each x-value is multiplied by 2 before the corresponding y-value is calculated. b. I think that y=ln(4-x) is a reflection in the y-axis followed by a translation by the vector...
  19. AN630078

    Rates of change: surface area and volume of a sphere

    Thank you very much for your reply. Would the correct units be dS/dt=120 π cm^2 s^-1 and dV/dt=300π cm^3 s^-1? Yes, indeed I did notice that the surface area is the derivative of the volume. Is this always true? 👍
  20. AN630078

    Rates of change: surface area and volume of a sphere

    The surface area of the sphere is 4πr^2. dr/dt is given as 3cm^-1. dS/dt=dS/dr*dr/dt Differentiating 4πr^2 is dS/dr= 8πr dS/dt=8πr*3 dS/dt=24πr Given that r=5 dS/dt=24π*5=120 π The volume of the sphere is 4/3πr^3, differentiating which is dV/dr=4πr^2 dV/dt=dV/dr*dr/dt dV/dt= 4πr^2*3...
  21. AN630078

    Coefficients in the expansion of (1+x)n in A.P, find n

    Thank you for your reply. Oh I see how silly of me, thank you for explaining how to find the common factors. Do you think that my solutions would be correct? Thank you for the suggestion to generate a Pascal triangle, how would this help here though? 😁
  22. AN630078

    Coefficients in the expansion of (1+x)n in A.P, find n

    Thank you very much for your reply. Oh I am sorry thank you for amending my mistake. Right, I greatly appreciate your help however I am still a bit confused. How did you identify 8! and (n-10)! as common factors? Would the next step be to find the LCM of the denominators which would be...
  23. AN630078

    Coefficients in the expansion of (1+x)n in A.P, find n

    https://www.toppr.com/ask/question/if-in-the-expansion-of-1-xn-the-coefficient-of-14th-15th-and-16th/ https://www.sarthaks.com/402983/if-in-the-expansion-of-1-x-n-the-coefficients-of-14-th-15-th-and-16-th-terms-are-in-a-p-find-n Specifically regarding my problem the coefficients of x^8, x^9 and...
  24. AN630078

    Van der Graaf Generator: Charge, Potential and Redesign Questions

    Thank you very much for your reply also. If the charge were greater would the generator begin to produce sparks? Thank you, yes sorry I missed that typo, and thank you for suggesting combining the formula to produce V=rE. I am still not sure about the redesign of the generator to raise the...
  25. AN630078

    Capacitor Questions Charging and Discharging

    Question 1: a. I am aware that the general equation for capacitance is C=Q/V thus Q=CV. 22 μF = 0.000022 or 2.2*10^-5 F Would the charge stored by equal to Q=2.2*10^-5*12 Thus, Q=2.64*10^-4 C b. The energy stored by a capacitor is given by E=1/2QV=1/2CV^2=1/2Q^2/C I think with the information...
  26. AN630078

    Van der Graaf Generator: Charge, Potential and Redesign Questions

    Thank you very much for taking the time to reply. Haha, yes I would have to agree, perhaps I have misunderstood the question and am searching for the "magic words". I am a little at a standstill though do you have any suggestions? 😊
  27. AN630078

    Van der Graaf Generator: Charge, Potential and Redesign Questions

    Thank you for your very swift reply 😁. Yes confessedly I do need to learn LATEX! So would I assume my solutions for question 1 are incorrect? The reason I quoted to such a extensive length of siginifcant figures was to show that the solutions I obtained convereged to whole solutions that did...
  28. AN630078

    Van der Graaf Generator: Charge, Potential and Redesign Questions

    1. i. I think that the potential on the surface will be the same as that of a point charge at the centre of the Van der Graaf sphere, which will be 30cm away (since this is the radius of the top sphere). Convert 30cm to m which is equal to 0.3 m. Therefore, to find the charge it can hold one can...
  29. AN630078

    Drawing Radial Field Equipotentials and Field Lines

    Thank you for your reply. I do not know what you mean by an iterative plotting procedure. In regard to an alternative unit for gravitational field strength, yes thank you for your suggestion I am aware of the use of m/s^2? However, would Jm^-1kg^-1 be a suitable alternative, although lesser used?
  30. AN630078

    Drawing Radial Field Equipotentials and Field Lines

    I have just attached a standard depiction of a radial field as one may similarly choose to draw it. So I understand that the gravitational field strength in a field is defined as the force per unit mass at that point. The field lines in a radial field move further apart further away from the...
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