Yeap. Thanks for the enlightenment. It was your reply that gave me the idea of how to do it.
You need to take into account that the ideal gas compresses, hence its pressure changes.
Thanks buddy . This thread can be closed now.
I got the answer already. as explained in my earlier edited message. Theres no need for the width value as when we calculate the volume ratios, they cancel out I guess.
Please comment on it .
Thanks a lot buddy!
From what i have. It should be something like this.
Let A be the answer.
Equation 1(Diagram 1) : Atmospheric pressure = Pressure from Ideal Gas(hpg) + Pressure in the mercury lever.
A x Density of Mercury x Gravity = 0.3 x Density of Gas x Gravity + 0.7 x Density of Mercury x Gravity...
[SOLVED] Pressure (Barometer)
A mercury barometer of height 1.000m has some ideal gas trapped inside. When the tube is vertical, the height of the mercury column is 0.700m. When the tube is inclined at an angle of 30 degrees to the horizontal, the length of the mercury is...