Lenses/Images -- Find final image
Two converging lenses, each having a focal length equal to 8 cm, are separated by 35 cm. An object is 30 cm to the left of the first lens.
(a) Find the position of the final image using both a ray diagram and the thin-lens equation
(c) What is the overall...
Heat/First Law of Thermodynamics/Calorimetry -- Have work done
A calorimeter of negligible mass contains 920 g of water at 303 K and 48 g of ice at 273 K. Find the final temperature T.
°C
Solve the same problem if the mass of ice is 460 g.
°C
Formula Ive used
Mice * Lf + Mice * Cwater *...
The period of an oscillating particle is 56 s, and its amplitude is 18 cm. At t = 0, it is at its equilibrium position. Find the distances traveled during these intervals.
(a) t = 0 to t = 14 s
cm
(b) t = 14 s to t = 28 s
cm
(c) t = 0 to t = 7 s
cm
(d) t = 7 s to t = 14 s
cm
x =...
Water flows at 0.67 m/s through a 3.0 cm diameter hose that terminates in a 0.35 cm diameter nozzle. Assume laminar non-viscous steady-state flow.
(a) At what speed does the water pass through the nozzle?
49.22 m/s
(b) If the pump at one end of the hose and the nozzle at the other end are...
Fluids -- pressure
Blood plasma flows from a bag through a tube into a patient's vein, where the blood pressure is 10 mmHg. The specific gravity of blood plasma at 37°C is 1.03. What is the minimum elevation the bag must have so the plasma flows into the vein?
Prof gave this problem for us...
h = V^2R^2/(2*u - V^2*R)
h = 13.69 * 40960000 / (800000 - 87616)
h = 560742400 / 712384
h = 787.1350283 km
h = .7871350283 m
Do I add this to the Radius of the earth?
well the textbook has the same problem explained but different velocity and it uses that equations and same steps I posted. But I don't know what I did wrong mathematically to give me a negative height. I was wondering if someone can work it out and see if they get the same answer or diff.
This is the final equation:
1/radius_f = -Vi^2/2*G*M_e + 1/R_e
then I solve for radius_f then I divide it by 1
then I subtract it from the earth's radius to get the height but it gives me a negative height.
Gravity -- maximum height
An object is projected upward from the surface of the Earth with an initial speed of 3.7 km/s. Find the maximum height it reaches.
m
Ive used the Energy conservation
Kf + Uf = Ki + Ui
1/2 mvf^2 - G*M_e*m/rf = 1/2 mvi^2 - G*M_e*m/ri
= 0 - G*M_e*m/rf = 1/2 mvi^2 -...
Yes, it makes sense, thanks for explaining.
And I got what r is now that you related it as a circle.
For part C:
What you said earlier
time = distance/speed
where distance is the orbits circumference/distance covered
It would be 2Pi*(86.37 x 10^6) / 2.15km
I get a big answer of 252528.6976s...
Ok, I got the mass of the earth 5.98 × 10^24 kilograms from the textbook.
So the raidus of the Earth is 6.37 x 10^6m which my textbook says.
So I add 8.00 x 10^7 m to it? So is 86,370,000 which is 86.37 x 10^6
gravitational Force = G*m1*m2 / r^2
G = 6.67 x 10^-11 Nm^2/kg^2
F = (6.67 x...
Gravity Problem -- satellite
A satellite with a mass of 250 kg moves in a circular orbit 8.00 x 10^7 m above the Earth's surface.
(a) What is the gravitational force on the satellite?
N
(b) What is the speed of the satellite?
km/s
(c) What is the period of the satellite?
h
Relevant Equations...