Search results

  1. X

    Kinetic friction on incline/flat surface system

    It seems I can't post the picture because it's from a site that has to be logged into. Basically, to the left is an incline on which the block starts. The length of the incline is the s1 listed. Then at the bottom of the incline the path levels off and the length of the level part is s2. The...
  2. X

    Kinetic friction on incline/flat surface system

    I already posted the pic, maybe you can't see it for some reason. Here's a link: EDIT: nevermind
  3. X

    Kinetic friction on incline/flat surface system

    Homework Statement http://nplq1.phyast.pitt.edu/res/msu/physicslib/msuphysicslib/13_EnergyConservation/graphics/prob27a_MechEnWFriction.gif When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 2.07 m/s. The mass stops a distance S2 = 1.9 m...
  4. X

    System of masses over a pulley

    Ah! I just got it right. I was using the wrong directiond for my sums. For the x sum on M1, I assumed right to be positive and for the y sum on Mw I assumed up to be positive. This doesn't work because I need to assume that the pulley only changes the direction, and therefore the downward...
  5. X

    System of masses over a pulley

    Numerically? 1.07 m, 0.802 m, and 2.14 m.
  6. X

    System of masses over a pulley

    Yes, I realize that the ension will be equal in both cases...that's what I was trying to account for but I'm not quite sure how to account for it. Like I said, I solved for T in the hanging mass and used that in for T in the first mass...wouldn't that be assuming they are equal?
  7. X

    System of masses over a pulley

    Homework Statement http://nplq1.phyast.pitt.edu/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob69_2blkplly.gif Two blocks are arranged as shown. The pulley can be considered to be massless, and friction is negligible. M1 is four times more massive than M2. If the...
  8. X

    A particle leaves the origin (motion in 2 dimensions)

    Thanks...I ended up getting the correct answers. Here's what I did: I set the first derivative of the equation you gave (which is essentially the basic formula v=v_0+at to zero to find at which time the maximum x would occur. Then I found the x and y velocity using that same formula but...
  9. X

    A particle leaves the origin (motion in 2 dimensions)

    Thank you both, I will try and use your advice to try and solve the problem. I don't understand the integration though...what exactly would I integrate to get the velocity? Velocity is the derivative of position with respect to time, so would the velocity be the integral of acceleration with...
  10. X

    A particle leaves the origin (motion in 2 dimensions)

    Homework Statement A particle leaves the origin with an initial velocity v = 3.92i , in m/s. It experiences a constant acceleration a = -1.00i -0.80j , in m/s2. What is the velocity of the particle when it reaches its maximum x coordinate? i-component of velocity? j-component of the...
  11. X

    Electric Field and Charge Density

    Right, I get that now. The integral would be evaluated from +x to infinity. Could someone point me to a place, or perhaps explain to me briefly, how substituting an infinity into an expression would affect it? I know that if infinity is ever in the denominator then the expression would be 0. Are...
  12. X

    Electric Field and Charge Density

    The charge is along a line that goes to infinity though...how would that work?
  13. X

    Electric Field and Charge Density

    Thanks for the help. I'll try and do that to see how it works out.
  14. X

    Electric Field and Charge Density

    Any pointer would be greatly appreciated.
  15. X

    Electric Field and Charge Density

    Homework Statement A line of charge starts at x=+x_0 and extends to positive infinity. If the linear charge density is \lambda=\frac{\lambda_0x_0}{x}, determine the electric field at the origin. The Attempt at a Solution I'm really not sire which equations I would have to use to solve...
  16. X

    Energy required to place a satellite in orbit

    I forgot to factor out the GMm, that would have made it so much easier haha. Iget it perfectly now, thanks so much for all the help! =)
  17. X

    Density of a planet using orbit of a satellite

    (\frac{R+h}{R})^3 can be simplified to (1+\frac{h}{R})^3 correct? If so, I've got the right answer correctly. Thanks so much!!
  18. X

    Energy required to place a satellite in orbit

    Wow, thanks! That all pretty much makes perfect sense to me...I just get a little lost in the last line when I need to add the fractions. Could you tell me how exactly the top line would combine so as to make the 2h appear? Thank you so much for your help.
  19. X

    Energy required to place a satellite in orbit

    I'm trying to subtract the two energy expressions but I'm either doing it completely wrong or I wasn't right in the first place.
  20. X

    Density of a planet using orbit of a satellite

    Yes, I see what you mean. But now I get that the density is \frac{3\pi}{GT^2R^2}(R+h)^3 So I have another R62 in the bottom there...is there a way I can bring that up and unclude it in the R+h ?
  21. X

    Density of a planet using orbit of a satellite

    [SOLVED] Density of a planet using orbit of a satellite Homework Statement A satellite is in a circular orbit about a planet of radius R. If the altitude of the satellite is h and its period is T, show that the density of the planet is \rho=\frac{3\pi}{GT^2}(1+\frac{h}{R})^3 The...
  22. X

    Energy required to place a satellite in orbit

    Doesn't -\frac{GmM_E}{2(R_E+h)} cover the entire energy of the satellite when it is in orbit?
  23. X

    Energy required to place a satellite in orbit

    [SOLVED] Energy required to place a satellite in orbit Homework Statement A 200-kg satellite is placed in Earth orbit 200 km above the surface. What is the minimum energy necessary to place this satellite in orbit (assuming no air friction)? The Attempt at a Solution To solve this...
  24. X

    Simple harmonic motion and friction

    Alright...thank you for the help!
  25. X

    Simple harmonic motion and friction

    In my book, it says that a=-\omega^2Acos(\omegat+\phi) So if I put in 2*pi*f for w, I get a=-4\pi^2f^2Acos(2ft\pi+\phi) OK, thanks now I can see where those quantities come from. OK, so the frictional force must not be greater than an acceleration given by this, right? I think I'm...
  26. X

    Simple harmonic motion and friction

    I see...but I don't have an amplitude, I need to find the maximum amplitude. I do see how the friction force is equal to ma though.
  27. X

    Simple harmonic motion and friction

    I suppose that my two biggest things that I can't get straight in my mind are where does the pi come from, and why is there no k needed to find the answer. Also, there should be an exponent of 2 on the pi in the denominator, sorry about that.
  28. X

    Simple harmonic motion and friction

    Homework Statement A large block P executes horizontal simple harmonic motion by sliding across a frictionless surface with a frequency f = 1.5 Hz. Block B rests on it, and the coefficient of static friction between the two is \mu_s=0.60. What maximum amplitude of oscillation can the system...
Top