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    X-radiation inverse square law

    Hi Rajani Thanks for all of your help May you have a very merry christmas and a healthy and prosperous 2011 cheers.
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    X-radiation inverse square law

    rajini, I've googled the inverse square law prior to asking these questions, and if i fully understood it i would not be asking the question. as i understand it so far the radiation strength at D1 is squared. ie 400mGy/hr @ 2m = 1600mGy/hr Then the distance at D2 is squared ie 6m = 36 The...
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    MSv/h to R/h

    Tiny-tim, Thanks again, i think i have a better grip on the concept now. 1 Sv = 100 rem 1 mS/h = 100 mR/h so 20mR/h =0.2 mS/h
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    X-radiation inverse square law

    Thanks again Tiny-Tim/Rajani Firstly Rajani, no i'm lost i cannot write the inverse square law formula. Secondly, Tiny-Tim again i'm lost in the meaning of (6/2)2 if you could put it more simply maybe i could grasp it and go from there. Thanks again
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    MSv/h to R/h

    Thanks for your help. I'll write the answer as above. I don't know any other way.
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    MSv/h to R/h

    Thanks Tiny-Tim So there must be a better way of expressing the answer?
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    X-radiation inverse square law

    Thanks Tiny-Tim, i think i'm getting closer 400mGy/hr at 2 meters should still be 400mGy/hr at 6m? then 400mGy/hr divided by the square of the distance ie 6m is that how it works?
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    MSv/h to R/h

    [b]1. How many mSv/h of x-radiation is equivalent to a dose rate of 20mR/h? [b]2. The relationship between the sievert and the Rem is i believe isievert = 100 Rem [b]3. answer i think 2000mSv/h
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    X-radiation inverse square law

    Hi, Thanks for the reply Yes i want to know the radiation level at 6m The only thing i know is the level is 400mGy/hr at 2m from a point radiation source. I do not know how to calculatate the rest. I thought 400mGy/hr at 2m might be a quarter of the original strength??
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    Raditation sheilding question

    Hey, i have a similar problem and the best ive come up with so far is the inverse square law, ie at 1m dose rate constant, at 2m the dose rate is the square of the distance thus at 3m equals 9m2 etc then the HVL of the shielding material is calculated by thickness required to absorb half of the...
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    X-radiation inverse square law

    [b]1. If the radiationlevel is 400mGy/hr at 2m from a point radiation source, what will be the radiation level at 6m [b]2. I figured that if the radiation was 400mGy/hr at 2m it have been 1600mGy/hr when emmitted from the sorce. [b]3. If the inverse square law works like at 2m...
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    Radiation levels

    Thanks for the reply OK so the radiation level at 6m is still 400mGy/hr but covering an area of 36m2 as per 400mGy/hr at 2m covering an area of 4m2 How come the x-radiation shielding HVL system has to be calculated? Why not just shield for the given dose rate regardless of distance, if...
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    Radiation levels

    Zhermes Q. If the radiation level is 400mGy/hr at 2m from a point source, what will be the radiation level be at 6m? Are you saying the radiation level will decrease by a factor of three? If at the piont of radiation the level is 1600mGy/hr, then at 2m it should represent a factor of four...
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    Radiation levels

    Using the inverse square law could anyone tell me what the outcome of this problem is? If the radiation level is 400mGy/hr at 2m from the point radiation source, what will be the radiation level at 6m? I figured it would be 1600mGy/hr at the point, and therefore 44.4mGy/hr at 6m being...
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