Yes, when the object is in freefall on Earth, gravity = a = 9.8m/s^2 down. Signs are optional but you could say -9.8n/s^s.
In 2D, the gravity is always 9.8m/s^2 down on the object.
It doesn't matter how the object is moving or thrown, gravity is always down.
Wait, I think it was the d for the 4th second, from 3-4s. Because the first second is 0-1s, second second is for 1-2s, etc.
V@3=5+9.8*3 and V@4=5+9.8*4
B=µoNI/2r, B is magnetic force, µo is magnetic constant, N is number of turns, I is current, r is radius
I think that's it but that R is unused in the problem, and it concerns me that I missed something.
R2 removed: 12=R1(I+.2)
R1 removed: 12=R2(I+.1)
Solve for R's
Plug into original equation
Solve for I
Plug I back into R1 and R2