Your inputs from the equation are X and Q so start with them
XQ
00
01
10
11
from this we fill out X' and Q'
X'Q'
11
10
01
00
using these columns solve Q+
for example the first part XQ = 0 0 = 0
the second part X'Q' = 1 1 = 1
0 or 1 = 1 therefore Q+ = 1
creating the characteristic table
X Q...
An irrigation system should open sprinkler's water valve = Z
when if
the system is enabled = A
and
neither raining = B'
nor freezing temperatures are detected. (same as or not freeze...) = C'
Z = AB' + C'
as defined above the and is multiplication, the or is addition
if it says not, neither or...
Homework Statement
Y
-----------1----2-----3------4
x---1----1/4----0-----0------0
----2----1/8----1/8---0------0
----3----1/12---1/12--1/12---0
----4----1/16---1/16--1/16--1/16
The Joint PMF of random varables X and Y is given in the table above
Let...
Homework Statement
Infinite unknown line charges of 5nC/m lie along the (positive and negative) x and y axes in free space. Find E at P(0,0,4)
Homework Equations
E = (pl/2(pi)(eo)p)ap
pi = 3.14...
eo - permitivity of free space 8.854 x 10^-12
pl = line charge density
ap = unit...
for Q1:
the right side of the circuit had a 6k and 4k resister in series, these 2 resistors can be replaced with a 10k resister (eqiv resistance between 2 resisters in series is the sum)
so the circuit is a 40 a current source then a 5k resister then has 10k and 20k resistors in parallel
the...
Q1, 6k and 4k resister are in series = 10k resister
the current through the 5k is 40amps then it splits between the new 10k and 20k resister (current divider)
I(through the 20K) = 40 (10/10+20) = 40(1/3) = 13.33 amps
Homework Statement
In free space, Q1 = 10nc at P1(0,-4,0) and Q2 = 20nC at P2(0,0,4).
a. Find E at the origin (answered)
E(r) = 5.617ay - 11.235az
b. Where should a 30nC point charge be located so E=0 at the origin? (need help)
Homework Equations
E(r) = (1/4(pi)epsilon) sum...