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1. How to determine a characteristic table and design a frequecy divider

Your inputs from the equation are X and Q so start with them XQ 00 01 10 11 from this we fill out X' and Q' X'Q' 11 10 01 00 using these columns solve Q+ for example the first part XQ = 0 0 = 0 the second part X'Q' = 1 1 = 1 0 or 1 = 1 therefore Q+ = 1 creating the characteristic table X Q...
2. Converting English to Boolean Algebra

An irrigation system should open sprinkler's water valve = Z when if the system is enabled = A and neither raining = B' nor freezing temperatures are detected. (same as or not freeze...) = C' Z = AB' + C' as defined above the and is multiplication, the or is addition if it says not, neither or...
3. Probability question using r.v. X and Y what is W=min(X,Y) ?

Homework Statement Y -----------1----2-----3------4 x---1----1/4----0-----0------0 ----2----1/8----1/8---0------0 ----3----1/12---1/12--1/12---0 ----4----1/16---1/16--1/16--1/16 The Joint PMF of random varables X and Y is given in the table above Let...
4. E Field of a line charge

Homework Statement Infinite unknown line charges of 5nC/m lie along the (positive and negative) x and y axes in free space. Find E at P(0,0,4) Homework Equations E = (pl/2(pi)(eo)p)ap pi = 3.14... eo - permitivity of free space 8.854 x 10^-12 pl = line charge density ap = unit...
5. Circuit analysis questions

for Q1: the right side of the circuit had a 6k and 4k resister in series, these 2 resistors can be replaced with a 10k resister (eqiv resistance between 2 resisters in series is the sum) so the circuit is a 40 a current source then a 5k resister then has 10k and 20k resistors in parallel the...
6. Circuit analysis questions

Q1, 6k and 4k resister are in series = 10k resister the current through the 5k is 40amps then it splits between the new 10k and 20k resister (current divider) I(through the 20K) = 40 (10/10+20) = 40(1/3) = 13.33 amps