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1. Reflection and Film Problem

Ah okay, thank you!
2. Reflection and Film Problem

Ah okay, so is my approach correct? And the textbook also notes that if the speed of the first medium is greater than the speed of the second medium, there will also be a phase shift of pi.
3. Reflection and Film Problem

And since the incidence is normal, cos(0)=1. Well, approximately 0, so cos(~0) = ~1
4. Reflection and Film Problem

Hmm.. I was doing some other research and I found some other equations for thin-film interference.. \huge \phi=\frac{4\pi n_b t \cos(\theta_i)}{\lambda}+\phi_{r2}-\phi_{r1} Could I make the assumption that since the speed will be greater in air than in the glass that it will experience a pi...
5. Reflection and Film Problem

n=\frac{550}{2(104)}=2.64
6. Reflection and Film Problem

Well, it would be destructive since it needs to cancel light. m should be at a minimum as well, which would be 1, right?
7. Reflection and Film Problem

Homework Statement You are designing a thin transparent reflective coating for the front surface of a sheet of glass. The index of refraction of the glass is 1.52 and when it is in use, the coated glass has air on both sides. Because the coating is expensive, you want to use a layer that has...
8. Diffraction Grating Relationship Question

Or perhaps since.. # of fringes = 2x+1, where x=m, then 2m+1 a). if m halves, then # of fringes = x+1 b). if m doubles, then # of fringes = 4x + 1 Or maybe I'm just overthinking it?
9. Diffraction Grating Relationship Question

Homework Statement A diffracting grating casts a pattern on a screen located a distance L from the grating. The central bright fringe falls directly in the center of the screen. For the highest-order bright fringe that hits the screen, m=x, and this fringe hits exactly on the screen edge. This...
10. Simple Circuit Problem

Will I have to each of the 4 joins since so far I only have 2 equations and 4 unknowns? Won't I end up with some more unknowns?
11. Simple Circuit Problem

Okay, so if I look at the joint above the voltage source.. there is a current entering from the bottom and current leaving on both the left and right sides. So I1-I2-I3=0 At join 2 (to the right of the resistor of the top), there is current entering from the left, and leaving out the right and...
12. Simple Circuit Problem

Ok! So I got that the equivalence resistance is 750 ohms. So now would I take 30V/750ohms to find the current?
13. Simple Circuit Problem

Okay, so the two that are in series on the two on the right, correct? And then in parallel would be the two ends?
14. Simple Circuit Problem

Okay, so now aren't these in series then? So you would just add them normally?
15. Simple Circuit Problem

Is this correct so far?
16. Simple Circuit Problem

Would it just be 1500 then? I'm a bit confused then about how to calculate it.. The two on the far right are in series so you add them and then next is the two that are on the right in parallel, so you would add the reciprocals. Then..? =/
17. Simple Circuit Problem

Homework Statement Assume the electric potential is zero at the negative terminal of the battery. Calculate: a). the equivalent resistance of the circuit b). the electric potential at position a c). the magnitude and direction of the current through each resistor Homework Equations The...
18. Nichrome and Copper Circuit w/ Electron Mobility

Ah that makes sense!! Thank you very much for your time and assistance!
19. Nichrome and Copper Circuit w/ Electron Mobility

I calculated the conductivity by using the information given in the initial problem. The reciprocal gives me the resistivity. I used that value in the resistance equation and that gave me R. Okay, so I calculated that both copper wires have voltage drops of 0.006V and the Nichrome has a voltage...
20. Nichrome and Copper Circuit w/ Electron Mobility

I absolutely hate circuits :) lol So the first part, the copper wire on top. V=IR, so the voltage at the end of the first resistor is V=531.42A*(1.13E-5) and that voltage continues until we hit the next resistor, yeah? 1.13E-5 is the R of copper
21. Nichrome and Copper Circuit w/ Electron Mobility

Okay, so I found the new total resistances. Copper stayed the same, but Nichrome's value did indeed change! So then the total current is I=V/R, so 1.5/.002823, which gives me 531.42A. So now I can apply V=IR to each piece?
22. Nichrome and Copper Circuit w/ Electron Mobility

Ohh, interesting. I did not see that in my search! So then the reciprocal would give me resistivity which would help me find resistance. So how would I find the new voltage in each piece of wire?
23. Nichrome and Copper Circuit w/ Electron Mobility

I'm not really sure how... I know that \sigma A V= I L where sigma is the conductivity. After solving for \sigma, I could take the reciprocal to get resistivity. From there plug in resistivity into the equation for resistance..? Not sure where the mobility comes into to play though.. I'm really...
24. Nichrome and Copper Circuit w/ Electron Mobility

R=\frac{\rho L}{A}=\frac{(1.49 \times 10^{-6}\Omega \cdot m)0.08m}{(2.83 \times 10^{-5}) m^2}=0.0042 \Omega
25. Nichrome and Copper Circuit w/ Electron Mobility

True. But either way the total resistance rounds to 0.0040A anyway. So I = 373.94 A. That seems very high doesn't it? I know that the resistivities are correct. As are the lengths and areas. So resistances is also correct..
26. Nichrome and Copper Circuit w/ Electron Mobility

Okay, I got that the resistance in the two copper wires are 1.13 \times 10^{-5} and the resistance in the Nichrome wire is 0.004. So V=IR I=V/R I=1.5/.0040113?
27. Nichrome and Copper Circuit w/ Electron Mobility

Oops -- ignore the 2 in the equation for resistance. Don't know why I put that there!
28. Nichrome and Copper Circuit w/ Electron Mobility

So let's say I want to find the voltage at the end of the copper wire on the left aka the new voltage for the start of the Nichrome wire on the left. The current through the copper wire is: I=V/R =\frac{1.5V}{\frac{2 \rho L}{A}}=\frac{1.5V}{\frac{2 (1.69 \times 10^{-8}) (0.17)}{2.54 \times...
29. Nichrome and Copper Circuit w/ Electron Mobility

Speaking of which, I have another question that seems like you would understand: R= \frac{\rho L}{A} So if I have half the area, that would mean that the resistance would double correct?
30. Nichrome and Copper Circuit w/ Electron Mobility

It's a very strange part of circuits that we haven't gone over, yet was included in the assignments, so it's kind of scaring me at the moment. I'm really not sure if I'm doing it correctly. Well, aren't resistivity and conductivity inverses of each other? so \sigma = \frac{1}{\rho} I guess I...