Hi everyone
I am looking at integrating this function,
\frac{dv}{dt}=g-\frac{c}{m}v
So far i have rearranged the function to get,
(\int1/g - \int1/(cv/m))* dv= \intdt
Thanks
JB
Hi
As fluid enters a pipe and progresses further down, does the shear stress at the wall reduce whilst the boundary layer increases and viscous forces take over?
Thanks
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