Homework Statement
I'm given three temperatures and four pressures for a heat exchanger. I am also given the mass flow rate, which is the same for both the inlets and outlets. There is no heat transfer between the heat exchanger and the surroundings. My task is to find the fourth...
1. Homework Statement
Obtain the pin-forces on the vertical bar BDE at the instant shown. Supply and document any additional information that my be necessary in order for this problem to have a tractable solution.
2. Homework Equations
Newton's motion equations. [I'm just trying to...
Homework Statement
Obtain the pin-forces on the vertical bar BDE at the instant shown. Supply and document any additional information that my be necessary in order for this problem to have a tractable solution. (This is number 3 in the attached pdf file.)
Homework Equations
Newton's...
Ok, I got the answer, but I want to make sure.
Is it x_n_ = x/n_2_
where x_n_ is the wavelength in the oil and x is the wavelength in air? n_2_ is the index of refraction of the oil or glass correct?
Thanks, by the way.
Homework Statement
Light of wavelength x, in air, is incident in air on a film of oil with index of refraction n_oil = 1.45. The film of oil has thickness L, and is spread on glass with an index of refraction n_glass = 1.50.
The wavelength of the light in oil will be _____ than the wavelength...
Homework Statement
The 4-kg uniform rod ABD is attached to the crank BC and is fitted with a small wheel that can roll without friction along a vertical slot. Knowing that at the instant shown crank BC rotates with an angular velocity of 6 rad/s clockwise and an angular acceleration of 15...
Ok, I found the answer. Linear momentum 4.9821*10^-25 kg * m/s
Angular momentum is 4.2182*10^-34 J*s
There are also three other parts to the question:
Find its kinetic energy, potential energy and total energy. (Use eV)
I found its kinetic energy (.850625eV), but I can't find its potential...
Homework Statement
A hydrogen is in the excited state of n=4. Using the Bohr theory of the atom, find the radius of the orbit.
Find the linear momentum of the electron. (kg*m/s)
Find the angular momentum of the electron. (J*s)
Homework Equations
r = a*n^2
??? maybe L =...
It's not really a problem, I'm doing an experiment where I hit an object with a hammer to see how far it travels. I have to determine whether the mass of the object affects how far it travels. Clearly it does, but I need some kind of relationship to prove it.
Shooting star, if I use the formula for constant acceleration, then I will end up with this:
(V^2-V_0^2)/(2*a) = \Delta x
If I use this equation with no acceleration, then I won't be able to get a distance because you can't divide by zero. Or, is the acceleration not zero?
Hi. I have a question about finding the distance an object will travel along a horizontal surface. If I have a force striking an object directly in the horizontal direction, how would I go about finding how far it will travel? I already have found the frictional force acting on the object...
Yes, it does say that she pulls a rope 48 degrees above the floor, but I'm not given that force, I'm given the horizontal component, which shows 567N. I attached a picture, but maybe it isn't working. I found the force along the rope to be about 847N, but that is not horizontal.
But that's what it says in the problem. "Sally applies a horizontal force of 567 N..."
Ah, so I would do -567N*34.1m? The work done by friction would be -19334.7J then?
The opposite direction. That leads me to believe that the force of friction is -567 N, but that doesn't make sense to me because if the forces are opposite and equal, then the crate shouldn't be moving.
The horizontal force on the crate is 567 N. The crate is not accelerating. The acceleration equals 0. Every sample problem in my book gives me the coefficient of friction. I really have no idea what to do. Maybe I do 567N/(9.8m/s^2), but that doesn't give me Joules.
That's something that I thought of too when I was working on the problem, but that makes me think that the answer is 0. But, I know that's not right. The only equation I know that gives the work done by friction is Wfk = -fk*d.
The last part of this problem has been bothering me. I don't understand how the work done by friction can be found if you are not given the coefficient of friction. Can anyone help me with this? There is a picture attached.
Homework Statement
Sally applies a horizontal force of 567N with a...