Given: A massless particle revolving in a circle with a rotational velocity = (2+sin(a))
To Find: Y-axis acceleration
Method #1 (from rotational acceleration)
Y-axis acceleration = (2+sin(a))(cos(a))^2
Method #2 (from Y-axis velocity)
Y-axis acceleration =...
You are done!
You just showed that I-T is invertible/bijective by showing that (I-T)(I+T) = (I+T)(I-T) = I. Which means, by definition, (I-T)^{-1} = (I+T)
Dr. Math has answered a lot of questions concerning the sum of consecutive squares here. He explains that there are several ways to derive the formula.
Linear Algebra-question. HELP!!
Problem:
Let L: R^3 \rightarrow R^4 be a linear transformation that satisfies:
L(e_1) = (2,1,0,1)^T = u
L(e_2) = (0,3,3,4)^T = v
L(e_3) = (2,-5,-6,-7)^T = w.
Determine a base for Range(L).
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Is the base \{u,v\} since w = u-2v? Is it really that...
Let f be that function defined by setting:
f(x) = x if x is irrational
= p sin(1/q) if x = p/q in lowest terms.
At what point is f continuous?
Continuous for irrational x, and for x = 0. Sketch:
p*sin(1/q) - p / q
= p(sin(1/q) -1/q)
But sin x - x = o(x^2) when x -> 0
So, for large...
There are totally 20 tires (17 proper and 3 defective).
Experiment 1: Pick one defective tire. One (exactly one) defective tire can be picked in \binom{3}{1} different ways.
Experiment 2: Pick three proper tires. This can be done in \binom{17}{3}
Using the basic principle of counting we...
Nvm, here we go. Let us assume that randomly selected means that each of the \binom{30}{4} combinations is equally likely to be selected. Hence the desired proability equals
\frac{\binom{18}{2}\binom{12}{2}}{\binom{30}{4}}
Scenario: Mr. X is writing letters to five persons A1, A2, A3, A4, A5. After Mr. X has written them he has to leave the room where the letters and envelopes are. Mr X's son, who can't read, decides to help his dad and puts each letter in different envelopes. What is the probability that:
a)...
A negative number can never lie within 0.01% of a positive number or vice versa. That just can't happen! So if (a,b) can be (2,-3) the problem don't make any sense! But you could try:
return (abs(max(a,b)/min(a,b)) <= 1.0001 && abs(min(a,b)/max(a,b)) >= 0.9999);
Note that before using...
Presumed that a, b are non-zero and both either positive or negative (at the same time). Then this should do it:
return (max(a,b)/min(a,b) <= 1.0001 && min(a,b)/max(a,b) >= 0.9999);
Don't forget to convert to SI units. The formulas you're suggesting are correct. To compare the acceleration to g is simple; divide the acceleration by g to get how many times it's greater than g.
We have, F = G\frac{Mm}{r^2}, and we want to solve for G.
G = \frac{Fr^2}{Mm}
The SI unit for mass is kg (kilogram) and for length it's m (meter). We know that:
{F = \frac{kg*m}{s^2}
With all this in mind we have that:
G = \frac{\frac{kg*m}{s^2}*m^2}{kg*kg}
Now all you have to...
Yes, indeed. The velocity has decreased down to zero which means that the acceleration must be negative. A negative acceleration is also called deceleration/retardation.
What you got must've been:
(x+6)^2 + (y+7)^2 + (z+1)^2-9^2 = 0.
The equation that describes the intersection with the plane z = 0 must be:
(x+6)^2 + (y+7)^2 + (0+1)^2-9^2 = (x+6)^2 + (y+7)^2 - 80 = 0